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3 years ago

A student completed a lab report. Which correctly describes the difference between the "Question" and "Hypothesis"

Biology

1 answer:

Vinil7 [7]3 years ago

5 0

Answer:

a question is something you ask about a topic, while a hypothesis is an educated guess/conclusion you draw from information you already have

Explanation:

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Hello humans I need help.

german

The correct answer would have to be 2 because it is on subject and is factual

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2 years ago

Read 2 more answers

Why is the cell membrane important?

andrew11 [14]

Answer:

The answer is A. The cell membrane provides rigid support and protection for the cell

Explanation:

The semipermeable structure that surrounds the cell helps the cell live in different environments

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3 years ago

In plants tall (T) is dominant to short (t) and round seed is dominant to wrinkled seeds (r). If a parent is short and wrinkled

Nuetrik [128]

Answer:

Parent cross= ttrr (short, wrinkled) × TtRr (hybrid)

POSSIBLE GAMETES BY EACH PARENT:

ttrr - tr, tr, tr, and tr

TtRr - TR, Tr, tR, and tr

Explanation:

This question involves two genes in a certain plant. One gene is coding for height while the other is coding for seed shape. The alleles for tallness (T) and round seeds (R) is dominant over the alleles for shortness (t) and wrinkled seeds (r).

According to this question, a parent that is short and wrinkled (ttrr) is crossed with another parent that is hybrid (TtRr) for both traits. This means that the parent cross is as follows: ttrr × TtRr

The possible combination of gametes that will be produced by each parent is as follows:

ttrr - tr, tr, tr, and tr

TtRr - TR, Tr, tR, and tr

See attached image for the punnet square using these gametes.

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3 years ago

How many calories per gram does fat release

jeyben [28]

Answer:

9 calories

Explanation:

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3 years ago

A fish maintains its depth in fresh water by adjusting the air content of porous bone or air sacs to make its average density th

Volgvan

Answer:

0.153

Explanation:

We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.

So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.

ρVg = ρ'V'g + ρ"V"g

ρV = ρ'V'g + ρ"V"

Its new body volume = volume of water displaced, V = V' + V"

ρ(V' + V") = ρ'V' + ρ"V"

ρV' + ρV" = ρ'V' + ρ"V"

ρV' - ρ"V' = ρ'V" - ρV"

(ρ - ρ")V' = (ρ' - ρ)V"

V'/V" = (ρ - ρ")/(ρ' - ρ)

= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)

= (0.9988 g/cm³ ÷ 0.18 g/cm³)

V'/V" = 5.55

Since V = V' + V"

V' = V - V"

(V - V")/V" = 5.55

V/V" - V"/V" = 5.55

V/V" - 1 = 5.55

V/V" = 5.55 + 1

V/V" = 6.55

V"/V = 1/6.55

V"/V = 0.153

So, the fish must inflate its air sacs to 0.153 of its expanded body volume

5 0

3 years ago