Question

Pls help need ASAP been stuck on these problems for a few now

Answer 1

Answer:

C. AC/BC = DF/EF

Step-by-step explanation:

Hi en that ∆ABC ~ ∆DEF, the corresponding sides of ∆ABC and ∆DEF would be proportional to each other.

AB corresponds to DE

AC corresponds to DF

BC corresponds to EF

Therefore,

hypotenuse over one of the leg of ∆ABC = hypotenuse over one of the corresponding legs of ∆DEF, which is:

AC/BC = DF/EF