Pls help need ASAP been stuck on these problems for a few now
1 answer:
Answer:
C. AC/BC = DF/EF
Step-by-step explanation:
Hi en that ∆ABC ~ ∆DEF, the corresponding sides of ∆ABC and ∆DEF would be proportional to each other.
AB corresponds to DE
AC corresponds to DF
BC corresponds to EF
Therefore,
hypotenuse over one of the leg of ∆ABC = hypotenuse over one of the corresponding legs of ∆DEF, which is:
AC/BC = DF/EF
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