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sergejj [24]
3 years ago
10

Pls help need ASAP been stuck on these problems for a few now

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

C. AC/BC = DF/EF

Step-by-step explanation:

Hi en that ∆ABC ~ ∆DEF, the corresponding sides of ∆ABC and ∆DEF would be proportional to each other.

AB corresponds to DE

AC corresponds to DF

BC corresponds to EF

Therefore,

hypotenuse over one of the leg of ∆ABC = hypotenuse over one of the corresponding legs of ∆DEF, which is:

AC/BC = DF/EF

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1. Which ordered pairs are solutions to the inequality –3x + y ≥ 7?
Murrr4er [49]
Q1. The answers are (–1, 8), (0, 7), (3, 18)

<span>–3x + y ≥ 7
</span>Let's go through all choices:

<span>(–2, –3) 
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6 - 3 ≥ 7
3 ≥ 7       INCORRECT

(–1, 8) 
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Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes

</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80

Jude needs at least 4 small boxes on the shelf: x ≥ 4

Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16

x ≥ 4 can include x ≤ 16

So, y can be 0: y ≥ 0
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3 years ago
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y=2
Then put the y value into the first equation to get x:
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There you go!

Please mark brainliest
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Which statement best describes the interquartile range of this set of weights?
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Answer:

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Step-by-step explanation:

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