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Marat540 [252]
3 years ago
11

Find the length in the first quadrant of the circle described by the polar equation r = 2 sin θ + 4 cos θ. The circle is graphed

in the accompanying figure. A. √2 π B. 5 π C. 2 π D. √5 π
Mathematics
1 answer:
Goryan [66]3 years ago
3 0
The rectangular form of the equation is

(x+2)^2 + (y+1)^2 = 5

r = sqrt(5)

then the answer is <span>D. √5 π</span>
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james trained for the boston marathon for 3(1/2) hours every day. how many hours did he train each week?
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Y = 3.5x
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4 years ago
18 – 12 + x = 10 What value of x makes the equation true?
drek231 [11]

Answer:

4

explanation:

well 18 minus 12 would equal 6. correct? so we would add x to 6 so the new equation would be 6 + x = 10 or to make it easier just do 10 - x = 6

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Janet plants 20 varieties of flowers in the spring . She reports that 90% of the flowers she have planted bloomed
SIZIF [17.4K]

Answer:

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Two points located on jk are j (-1,-9) and k (5,3). What is the slope of jk?
Ivenika [448]

Answer:

2

Step-by-step explanation:

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slope of JK

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7 0
3 years ago
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Find parametric equations for the sphere centered at the origin and with radius 3. Use the parameters s and t in your answer.
sdas [7]
Radius, r = 3

The equation of a sphere entered at the origin in cartesian coordinates is

x^2 + y^2 + z^2 = r^2 

That in spherical coordinates is:

x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)

where you can make u = r cos(phi) to obtain the parametrical equations

x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u

where theta goes from 0 to 2π and u goes from -r to r.

In our case r = 3, so the parametrical equations are:

Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
6 0
3 years ago
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