Answer:
We are given that According to government data, 75% of employed women have never been married.
So, Probability of success = 0.75
So, Probability of failure = 1-0.75 = 0.25
If 15 employed women are randomly selected:
a. What is the probability that exactly 2 of them have never been married?
We will use binomial
Formula : ![P(X=r) =^nC_r p^r q^{n-r}](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%5EnC_r%20p%5Er%20q%5E%7Bn-r%7D)
At x = 2
![P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%5E%7B15%7DC_2%20%280.75%29%5E2%20%280.25%5E%7B15-2%7D)
![P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}](https://tex.z-dn.net/?f=P%28X%3D2%29%20%3D%5Cfrac%7B15%21%7D%7B2%21%2815-2%29%21%7D%20%280.75%29%5E2%20%280.25%5E%7B13%7D)
![P(X=2) =8.8009 \times 10^{-7}](https://tex.z-dn.net/?f=P%28X%3D2%29%20%3D8.8009%20%5Ctimes%2010%5E%7B-7%7D)
b. That at most 2 of them have never been married?
At most two means at x = 0 ,1 , 2
So, ![P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%5E%7B15%7DC_0%20%280.75%29%5E0%20%280.25%5E%7B15-0%7D%2B%5E%7B15%7DC_1%20%280.75%29%5E1%20%280.25%5E%7B15-1%7D%2B%5E%7B15%7DC_2%20%280.75%29%5E2%20%280.25%5E%7B15-2%7D)
![P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D%280.75%29%5E0%20%280.25%5E%7B15-0%7D%2B15%20%280.75%29%5E1%20%280.25%5E%7B15-1%7D%2B%5Cfrac%7B15%21%7D%7B2%21%2815-2%29%21%7D%20%280.75%29%5E2%20%280.25%5E%7B15-2%7D%29)
![P(X=r) =9.9439 \times 10^{-6}](https://tex.z-dn.net/?f=P%28X%3Dr%29%20%3D9.9439%20%5Ctimes%2010%5E%7B-6%7D)
c. That at least 13 of them have been married?
P(x=13)+P(x=14)+P(x=15)
![={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})](https://tex.z-dn.net/?f=%3D%7B15%7DC_%7B13%7D%280.75%29%5E%7B13%7D%20%280.25%5E%7B15-13%7D%29%2B%7B15%7DC_%7B14%7D%20%280.75%29%5E%7B14%7D%280.25%5E%7B15-14%7D%2B%7B15%7DC_%7B15%7D%20%280.75%29%5E%7B15%7D%20%280.25%5E%7B15-15%7D%29)
![=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})](https://tex.z-dn.net/?f=%3D%5Cfrac%7B15%21%7D%7B13%21%2815-13%29%21%7D%280.75%29%5E%7B13%7D%20%280.25%5E%7B15-13%7D%29%2B%5Cfrac%7B15%21%7D%7B14%21%2815-14%29%21%7D%20%280.75%29%5E%7B14%7D%280.25%5E%7B15-14%7D%2B%7B15%7DC_%7B15%7D%20%280.75%29%5E%7B15%7D%20%280.25%5E%7B15-15%7D%29)
![=0.2360](https://tex.z-dn.net/?f=%3D0.2360)
Answer:
x = -1
Step-by-step explanation:
(-1 , 6) ; (-1 , -5)
There is no change in x-coordinate values.
So, the is parallel to y-axis
x = -1
Answer:
a) max 12000 , min 0
b) no solution
c) pricing based on profit
Step-by-step explanation:
a) look at the parabola
b) there is more than one x (0)
c) the y intercepts represent his profit based on how much he priced the items at
Answer:
c^2=a^2+b^2
c^2=6^2+8^2
c^2=36+64
c=10
but still do not understand why peoples are asking that basic
Are you trying to find x? send the whole question xoxo