3 years ago

CAN SOMEONE HELP ME PLEASE

1 answer:

6 0

Answer:

$\frac{\sqrt{189x^3y^6} }{\sqrt{3x} } \\= \frac{\sqrt{3^2(7)(3)(x^2)(x)(y^3)^2} }{\sqrt{3x} } \\=\sqrt{\frac{(3xy^3)^2(7)(3x)}{3x} }\\=3xy^3\sqrt{7}$

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ser-zykov [4K]

Step-by-step explanation:

Both are very correct,

$5 { }^{ - 2} = \frac{1}{25} \: or \: \frac{1}{5 {}^{2} }$

because any number raised to the power of a negative

is given as

$a {}^{ - x} = \frac{1}{a {}^{x} }$

if this helped pls give brainliest

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3 years ago

Dmitrij [34]

Answer:

-2 Celsius >-5 Celsius is the answer.

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Nana76 [90]

Answer:

no I do not agree, Because it doesn't make since

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Likurg_2 [28]

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dedylja [7]

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