Question: The graph of a second-order polynomial is shown below, and the intercepts with the axes are marked. Explain how you ca
n use the graph to write the polynomial as a product of linear factors (x-a)(x-b). Be sure to state the values of a and b.
NEED HELP ASAP
NEED HELP ASAP
1 answer:
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Answer:
See attached
Step-by-step explanation:
The graph of a <u>proportional linear relationship</u> is a line that <u>passes through the origin</u> (0, 0).
From inspection of the given tables, the <u>linear equations</u> for each table of points is:
- Table 1: y = x + 1
- Table 2: y = x/2
- Table 3: y = x + 2
- Table 4: y = 2x + 1
The only equation for which y = 0 when x = 0 is y = x/2 → Table 2.
Given points from Table 2:
- (2, 1)
- (4, 2)
- (6, 3)
- (8, 4)
To <u>graph the line</u>, plot the given points and draw a line through them (see attached).
The required equation is y=8×(
Step-by-step explanation:
Given,
The two points are (1,2) and (0.5,4)
To find the exponential equation of these given points.
Formula
The general form of exponential equation is y = where, A and B are any real number.
Now, the points satisfy the equation.
So,
2 = ------- (1) and
4 = ------ (2)
Now (1) ÷ (2) we get,
=
or, =
or, b = [ by squaring we get]
Now, from (1) we get,
2 = a×
or, a = 8
Hence,
The equation is y=8×(