Question: The graph of a second-order polynomial is shown below, and the intercepts with the axes are marked. Explain how you ca
n use the graph to write the polynomial as a product of linear factors (x-a)(x-b). Be sure to state the values of a and b.
NEED HELP ASAP
NEED HELP ASAP
1 answer:
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Answer:
y = -x + 4
Step-by-step explanation:
The point-slope formula for a straight line is
y – y₁ = m(x – x₁)
x₁ = -1; y₁ = 5; m = -1 Substitute the values
y – 5 = -1(x + 1) Remove parentheses
y – 5 = -x - 1 Add 5 to each side
y = -x + 4
The graph is a straight line with a y-intercept at y = +4 and a slope = -10/10
= -1.
