F ( x ) = 6 x³ - 13 x² - 4 x + 15
f ( - 1 ) = 6 · ( - 1 ) - 13 · 1 - 4 · ( - 1 ) + 15 = - 6 - 13 + 4 + 15 = - 19 + 19 = 0
( 6 x³ - 13 x² - 4 x + 15 ) : ( x + 1 ) = 6 x² - 19 x + 15
-6 x³ - 6 x²
--------------------
- 19 x² - 4 x
+ 19 x² + 19 x
----------------------
15 x + 15
-15 x - 15
------------
R ( x ) = 0
After that:
6 x² - 19 x + 15 = 6 x² - 10 x - 9 x + 15 =
= 2 x( 3 x - 5 ) - 3 ( 3 x - 5 ) = ( 3 x - 5 ) ( 2 x - 3 )
Answer:
The completely factored form is: ( x + 1 ) · ( 3 x - 5 ) · ( 2 x - 3 )
70 miles per hour for 9 hours gets Dustin 630 miles toward his goal.
Dustin has 236 miles to go.
Answer:
The correct answer would be 10ft
Answer:
The probability of a bulb lasting for at most 606 hours is 0.9032
Step-by-step explanation:
The mean lifetime of a bulb is 580 hours.
![\mu = 580 hours](https://tex.z-dn.net/?f=%5Cmu%20%3D%20580%20hours)
The standard deviation of the lifetime is 20 hours
![\sigma = 20 hours](https://tex.z-dn.net/?f=%5Csigma%20%3D%2020%20hours)
We are supposed to find the probability of a bulb lasting for at most 606 hours i.e. ![P(X\leq 606)](https://tex.z-dn.net/?f=P%28X%5Cleq%20606%29)
Formula :![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![Z=\frac{606-580}{20}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7B606-580%7D%7B20%7D)
Z=1.3
Refer the z table
![P( X \leq 606)=0.9032](https://tex.z-dn.net/?f=P%28%20X%20%5Cleq%20606%29%3D0.9032)
Hence the probability of a bulb lasting for at most 606 hours is 0.9032
Answer: 24
Step-by-step explanation: she can make 24 sandwiches because 1/32 times 24 = 3/4
hope this helps