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3 years ago

13

What is the definition of Slope

2 answers:

jeka943 years ago

5 0

Answer:

y/x

Step-by-step explanation:

rise over run

icang [17]3 years ago

4 0

Answer:

Slope is the 'steepness' of the line, also commonly known as rise over run (y/x)

Step-by-step explanation:

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200 cm and 200 dm which one is bigger

juin [17]

Answer

200 DM

Hope this helps

3 0

2 years ago

What is .the quotient -5 and y ??

stepladder [879]

Answer:

5 is = to 6 . 4 is equal to x so y is 64 divided bye 5 witch is 12

Step-by-step explanation:

8 0

3 years ago

Keisha sold hats and shirts at a festival. She made $36 from selling hats. She also sold x shirts and made $9 for each shirt. Sh

Solnce55 [7]

Answer:

36+9x=99

x=7

Step-by-step explanation:

36+9x=99

Subtract 99 and 36:

63

9x=63

Divide:

x=7

8 0

3 years ago

Read 2 more answers

Find the sum.<br> 5+ (-7)

vazorg [7]

Answer:

-2

Step-by-step explanation:

5 + (-7)

5 - 7

-2

Please let me know if something's wrong!

5 0

3 years ago

Х- а<br>x-b<br>If f(x) = b.x-a÷b-a + a.x-b÷a - b<br>Prove that: f (a) + f(b) = f (a + b)

GenaCL600 [577]

Given:

Consider the given function:

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot(x-b)}{a-b}$

To prove:

$f(a)+f(b)=f(a+b)$

Solution:

We have,

$f(x)=\dfrac{b\cdot(x-a)}{b-a}+\dfrac{a\cdot (x-b)}{a-b}$

Substituting $x=a$ , we get

$f(a)=\dfrac{b\cdot(a-a)}{b-a}+\dfrac{a\cdot (a-b)}{a-b}$

$f(a)=\dfrac{b\cdot 0}{b-a}+\dfrac{a}{1}$

$f(a)=0+a$

$f(a)=a$

Substituting $x=b$ , we get

$f(b)=\dfrac{b\cdot(b-a)}{b-a}+\dfrac{a\cdot (b-b)}{a-b}$

$f(b)=\dfrac{b}{1}+\dfrac{a\cdot 0}{a-b}$

$f(b)=b+0$

$f(b)=b$

Substituting $x=a+b$ , we get

$f(a+b)=\dfrac{b\cdot(a+b-a)}{b-a}+\dfrac{a\cdot (a+b-b)}{a-b}$

$f(a+b)=\dfrac{b\cdot (b)}{b-a}+\dfrac{a\cdot (a)}{-(b-a)}$

$f(a+b)=\dfrac{b^2}{b-a}-\dfrac{a^2}{b-a}$

$f(a+b)=\dfrac{b^2-a^2}{b-a}$

Using the algebraic formula, we get

$f(a+b)=\dfrac{(b-a)(b+a)}{b-a}$ $[\because b^2-a^2=(b-a)(b+a)]$

$f(a+b)=b+a$

$f(a+b)=a+b$ [Commutative property of addition]

Now,

$LHS=f(a)+f(b)$

$LHS=a+b$

$LHS=f(a+b)$

$LHS=RHS$

Hence proved.

5 0

2 years ago