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eduard
1 year ago
12

New session is here

Mathematics
1 answer:
Genrish500 [490]1 year ago
3 0

hey

^{9807}

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Find the x-coordinate of the vertex, y-coordinate of the vertex, and the x-intercepts.
galina1969 [7]

Answer:

X=-1

Y=-9

Step-by-step explanation:

x^2+2x-8

x^2+2x +1 =8+1

(x+1)-9

3 0
3 years ago
F(x)=x^2+3x ... find f(2-a)
olga2289 [7]
(2-a)^2 + 3(2-a)




A^2 -2a + 4 + 6 -3a



A^2 -5a +10
7 0
3 years ago
Read 2 more answers
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
3 years ago
5. Marie buys 2 pounds of turkey and 1 pounds of ham. She pays a total of $20,
NARA [144]

Answer:Let t = cost per pound of turkey

Let h = cost per pound of ham

 

4t + 2h = 30

t = h - 1.5

 

substitute h-1.5 in place of t in 1st equation

 

4(h-1.5) + 2h = 30

4h - 6 + 2h = 30

6h - 6 = 30

6h = 36

h = 6

 

t = h-1.5 = 4.5

 

1 pound of turkey costs $4.50

1 pound of ham costs    $6.00

                                ----------

cost of 1 pound each  $10.50

Step-by-step explanation:

8 0
2 years ago
Whats 3+3 for a prize~!<br>u&gt;
Vladimir [108]
3+3=6 hope this helps!
4 0
3 years ago
Read 2 more answers
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