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fgiga [73]
3 years ago
7

How to solve 2x²-8x-90=0

Mathematics
1 answer:
8090 [49]3 years ago
4 0
А=2
b=-8
c=-90
D=b^2-4ac
D=64+720
D=784=28^2
X1,2=(-b-+D):2a
Х1,2=(8+-28):4
Х1=-5
Х2=9
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What is 8-p/2 is less than or equal to 4?
Vanyuwa [196]
Less than (yes) p > -4

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3 years ago
Solve the equation 2x^2-3x-6=0 give your answer correct to two decimal places
IRISSAK [1]

Answer:

<h2>x = - 1.14 or x = 2.64</h2>

Step-by-step explanation:

2x² - 3x - 6 = 0

Using the quadratic formula

x =  \frac{ - b± \sqrt{ {b}^{2}  - 4ac} }{2a}

a = 2 , b = - 3 , c = 6

Substituting the values into the above formula

We have

x =  \frac{ -  - 3± \sqrt{ { - 3}^{2}  - 4(2)( - 6)} }{2(2)}

x =  \frac{3± \sqrt{9 +48 } }{4}

x =  \frac{3± \sqrt{57} }{4}

x =  \frac{3 -  \sqrt{57} }{4}  \:  \:  \:  \: or \:  \:  \:  \:  \: x =  \frac{3 +  \sqrt{57} }{4}

We have the final answer as

<h3>x = - 1.14 or x = 2.64</h3>

Hope this helps you

6 0
3 years ago
Given the following information
kicyunya [14]

Answer:

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3 0
3 years ago
Please help me with the below question.
VMariaS [17]

By letting

y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}

we get derivatives

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y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}

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Examine the lowest degree term \left(x^{r-1}\right), which gives rise to the indicial equation,

5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients c_k is

(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}

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c_1 = -\dfrac{c_0}5 = -\dfrac15

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\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}

4 0
2 years ago
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larisa [96]
1 and a fourth because 3 3/4 devided by three equals 1 1/4
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3 years ago
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