All categories

2 years ago

Plssssssssssssssssssssss helpppp

Mathematics

2 answers:

olga2289 [7]2 years ago

7 0

The answer should be 2kg

morpeh [17]2 years ago

5 0

Answer:

I think its 2 kg anyone correct me if I'm wrong!

You might be interested in

Translate this sentence into an equation. 48 is the product of Greg’s score and 3. Use the variable g to represent Greg’s score

ratelena [41]

Answer:

G x 3 = 48

Step-by-step explanation:

let G be Greg's score

And product means multiplication.

so G x 3 = 48.

finding Greg's score means 3g = 48.

g = 48/3

g = 16.

6 0

2 years ago

The ratio of boys to girls in Mrs. Miller's class is 2:3. If there are 8 boys in her class, how many girls are there?

Alenkasestr [34]

Answer:12

for every 2 boys that is 3 girls

there are 4 sets of two boys so you would have 4 sets of 3 girls

4×3=12

I hope this is good enough:

7 0

2 years ago

If 12x +1 =-7, what’s is the value of x over 8

Sergio [31]

12x+1=-7
-1 -1
12x=-6
/12 /12

x=-1/2 or x=-0.5

8 0

3 years ago

What is the slope of the line that passes through the points (-2,-1) and (2,-3) answer in simplest form

erma4kov [3.2K]

Answer:

Step-by-step explanation:

(-3 + 1)/(2 + 2)= -2/4= -1/2 is the slope

5 0

2 years ago

Find a power series for the function, centered at c. g(x) = 4x x2 2x − 3 , c = 0

BartSMP [9]

The power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

For given question,

We have been given a function g(x) = 4x / (x² + 2x - 3)

We need to find a power series for the function, centered at c, for c = 0.

First we factorize the denominator of function g(x), we have:

$\Rightarrow g(x)=\frac{4x}{(x-1)(x+3)}$

We can write g(x) as,

$\Rightarrow g(x)=\frac{1}{x-1}+\frac{3}{x+3}\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1+\frac{x}{3} }\\\\\Rightarrow g(x)=\frac{-1}{1-x}+\frac{1}{1-(-\frac{x}{3} )}\\$

We know that, $\frac{1}{1-x}=\sum{_{n=0}^\infty}~{x^n}$ if |x| < 1

and $\frac{1}{1-(-\frac{x}{3} )}=\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n$ if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=-\sum{_{n=0}^\infty}~x^n+\sum{_{n=0}^\infty}~x^n(-\frac{x}{3} )^n\\$ if |x| < 1 and if $|\frac{x}{6}| < 1$

$\Rightarrow g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$ if |x| < 1

Therefore, the power series for given function $g(x)=\frac{4x}{(x-1)(x+3)}$ is $g(x)=\sum{_{n=0}^\infty}~x^n(-1+(-\frac{x}{3} )^n)$

Learn more about the power series here:

brainly.com/question/11606956

#SPJ4

5 0

1 year ago

Plssssssssssssssssssssss helpppp​

Plssssssssssssssssssssss helpppp