Match each date to the correct description.

Write down the conservation of momentum?

otez555 [7]

Law of conservation of momentum states that when two objects collide with each other , the sum of their linear momentum always remains same or we can say conserved and is not effected by any action, reaction only in case is no external unbalanced force is applied on the bodies.
Let,
m
A

= Mass of ball A
m
B

= Mass of ball B
u
A

= initial velocity of ball A
u
B

= initial velocity of ball B
v
A

= Velocity after the collision of ball A
v
B

= Velocity after the collision of ball B
F
ab

= Force exerted by A on B
F
ba

= Force exerted by B on A
Now,
Change in the momentum of A= momentum of A after the collision - the momentum of A before the collision
= m
A

v
A

−m
A

u
A

Rate of change of momentum A= Change in momentum of A/ time taken
=
t
m
A

v
A

−m
A

u
A

Force exerted by B on A (F
ba

);
F
ba

=
t
m
A

v
A

−m
A

u
A

........ [i]
In the same way,
Rate of change of momentum of B=
t
m
b

v
B

−m
B

u
B

Force exerted by A on B (F
ab

)=
F
ab

=
t
m
B

v
B

−m
B

u
B

.......... [ii]
Newton's third law of motion states that every action has an equal and opposite reaction, then,
F
a

b=−F
b

a [ ' -- ' sign is used to indicate that 1 object is moving in opposite direction after collision]

Using [i] and [ii] , we have
t
m
B

v
B

−m
B

u
B

=−
t
m
A

v
A

−m
A

u
A

m
B

v
B

−m
B

u
B

=−m
A

v
A

+m
A

u
A

Finally we get,
m
B

v
B

+m
A

v
A

=m
B

u
B

+m
A

u
A

This is the derivation of conservation of linear momentum.

5 0

3 years ago

Distinguish between speed and velocity?<br>atleast 4 point should write

Sergio [31]

Answer:

mark me as brainliest ❤️

4 0

3 years ago

Two ideal gases have the same mass density and the same absolute pressure. One of the gases is helium (He), and its temperature

Oxana [17]

Answer:

Temperature of neon gas = 875 K

Explanation:

Using Ideal gas equation as:

PV=nRT

Where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the temperature

Also,

$moles=\frac{Mass(m)}{Molar\ mass (M)}$

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

The ideal gas equation can be written as:

$P=\frac{Mass(m)}{Molar\ mass (M)\times Volume(V)}\times RT$

Thus,

$P=\frac{Density (\rho)}{Molar\ mass (M)}\times RT$

$P\times M=Density (\rho)\times RT$

As Density and Pressure is constant , We only consider molar mass and Temperature which are directly proportional according to the equation above as:

$\frac {M_1}{T_1}=\frac {M_2}{T_2}$

Data given for He:

Temperature (T₁) = 175 K

Molar mass of He (M₁)= 4 g/mol

For Ne:

Temperature (T₂)= ?

Molar mass of He (M₂)= 20 g/mol

Applying in the equation,

$T_2=\frac {M_2}{T_1} \times {M_1}$

$T_2=\frac {20 g{mol}^{-1}}{175 K} \times {4 g{mol}^{-1}}$

$T_2=875 K atm$

<u>Temperature of neon gas = 875 K</u>

4 0

3 years ago

How many electrons or protons are found in

raketka [301]

a) $6.25\cdot 10^{18}$ protons

b) $6.25\cdot 10^{18}$ electrons

c) 1 electron

Explanation:

a)

In this problem, the electric charge that we have is:

$Q=+1 C$

First of all, we observe that this charge is positive: this means that it will consist of protons.

In fact, protons are positively charged particles that reside in the nuclei of the atoms. The charge of one proton is

$q_p = +1.6\cdot 10^{-19}C$

which is also known as fundamental charge.

Therefore, we can write the charge Q as consisting of the charge of several protons:

$Q=N q_p$

where N is the number of protons.

And solving for N,

$N=\frac{Q}{q_p}=\frac{+1}{+1.6\cdot 10^{-19}}=6.25\cdot 10^{18}$

b)

Here the total charge is

$Q=-1C$

The total charge here is negative: this means that it consists of electrons. Electrons are negatively charged particles that orbit around the nucleus in an atom; the charge of one electron is

$q_e = -1.6\cdot 10^{-19}C$

So, its charge is opposite to that of the proton.

Therefore, we can write the charge Q as the sum of the charges of N electrons:

$Q=Nq_e$

Where N is the number of electrons.

And solving for N, we find:

$N=\frac{Q}{q_e}=\frac{-1}{-1.6\cdot 10^{-19}}=6.25\cdot 10^{18}$

c)

In this case, the total net charge is

$Q=-1.6\cdot 10^{-19} C$

As in part b), we notice that the total charge is negative. Therefore, it will consist of N electrons (negatively charged particles), such that we have

$Q=Nq_e$

where

$q_e = -1.6\cdot 10^{-19}C$ is the charge of one electron

N is the number of electrons

And solving for N, we find:

$N=\frac{Q}{q_e}=\frac{-1.6\cdot 10^{-19}}{-1.6\cdot 10^{-19}}=1$

So, 1 electron.

3 0

3 years ago

A circuit has a current of 1.2 A. If the voltage decreases to one-third of its original amount while the resistance remains cons

rosijanka [135]

Answer:

1.2*1/3

Explanation:

Multiply the current by the volatage to get ur ans

6 0

4 years ago