A block slides down a frictionless plane having an inclination of 15.0°. The block starts from rest at the top, and the length o
f the incline is 2.00 m.Find its speed when it reaches the bottom of the incline.
1 answer:
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Answer:
Do find the answer in the attachment herein.
Explanation:
From the attached diagram:
I. Activation energy = Activated complex - ∆H(reactants)
Activation energy = 162-140 = 22Kj.
II. ∆H(reaction) = ∆H(products) - ∆H(reactants)
∆H(reaction) = 37 - 140 = -103Kj.
