Answer:
gravitational potential energy
Answer:
(a) 
, 
(b) When 
, object is slowing down, when 
object is speeding up.
Explanation:
(a) To get the velocity function, we need to take the derivative of the position function.
To get the acceleration function, we need to take the derivative of the velocity function.
(b) The object is slowing down when velocity is decreasing by time (decelerating) hence a < 0
On the other hand, object is speeding up when a > 0
Therefore, when 
, object is slowing down, when object is speeding up.
Kirchhoff's circuit laws are two equalities that deal with the current and potential difference (commonly known as voltage) in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff. This generalized the work of Georg Ohm and preceded the work of Maxwell.
Answer:
Explanation:
A ) When gymnast is motionless , he is in equilibrium
T = mg
= 63 x 9.81
= 618.03 N
B )
When gymnast climbs up at a constant rate , he is still in equilibrium ie net force acting on it is zero as acceleration is zero.
T = mg
= 618.03 N
C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2
Net force on it = T - mg , acting in upward direction
T - mg = m a
T = mg + m a
= m ( g + a )
= 63 ( 9.81 + .6)
= 655.83 N
D ) If the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s2
Net force acting in downward direction
mg - T = ma
T = m ( g - a )
= 63 x ( 9.81 - .6 )
= 580.23 N
