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Kaylis [27]
2 years ago
10

1. Boyle's law relates the pressure of a gas to its

Physics
1 answer:
KIM [24]2 years ago
7 0

Answer:

volume is the correct answer

Explanation:

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A drag racing car with a weight of 1600 lbf attains a speed of 270 mph in a quarter-mile race. Immediately after passing the tim
Kaylis [27]

Answer:

15.065ft

Explanation:

To solve this problem it is necessary to consider the aerodynamic concepts related to the Drag Force.

By definition the drag force is expressed as:

F_D = -\frac{1}{2}\rho V^2 C_d A

Where

\rho is the density of the flow

V = Velocity

C_d= Drag coefficient

A = Area

For a Car is defined the drag coefficient as 0.3, while the density of air in normal conditions is 1.21kg/m^3

For second Newton's Law the Force is also defined as,

F=ma=m\frac{dV}{dt}

Equating both equations we have:

m\frac{dV}{dt}=-\frac{1}{2}\rho V^2 C_d A

m(dV)=-\frac{1}{2}\rho C_d A (dt)

\frac{1}{V^2 }(dV)=-\frac{1}{2m}\rho C_d A (dt)

Integrating

\int \frac{1}{V^2 }(dV)= - \int\frac{1}{2m}\rho C_d A (dt)

-\frac{1}{V}\big|^{V_f}_{V_i}=\frac{1}{2m}(\rho)C_d (\pi r^2) \Delta t

Here,

V_f = 60mph = 26.82m/s

V_i = 120.7m/s

m= 1600lbf = 725.747Kg

\rho = 1.21 kg/m^3

C_d = 0.3

\Delta t=7s

Replacing:

\frac{-1}{26.82}+\frac{1}{120.7} = \frac{1}{2(725.747)}(1.21)(0.3)(\pi r^2) (7)

-0.029 = -5.4997r^2

r = 2.2963m

d= r*2 = 4.592m \approx 15.065ft

4 0
3 years ago
I am boring and you can talk to me?
sladkih [1.3K]
SURE HI



HI HOW R U


Hello
4 0
2 years ago
Read 2 more answers
1HP is written in an electric motor. what does it mean?​
romanna [79]

Answer:

1HP is 1 Horse Power,

Explanation:

3 0
3 years ago
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Which two components must a vector quantity
Lemur [1.5K]

Answer:

d. Direction and magnitude

Explanation:

The two components of a vector are its magnitude and direction.

Magnitude is the quantity of the substance

Direction is the path.

  • Other quantities are called scalar quantities.
  • Scalar quantities have only magnitude but no direction.

Examples of vector quantities are velocity, displacement, acceleration.

4 0
3 years ago
Find the angle between two equal forces (p) when their resultant is equal to (p)<br>​
Alexus [3.1K]

Answer:

60°

Explanation:

It will be equilateral triangle, you can prove with the cosine theorem.

1)P^2=P^2+P^2 - 2×P×P× cos A

2) cos A= P^2 / 2× P^2 = 1/2

cos A = 1/2

A = 60°

If you wrote this question right,it will be solved like this :)

4 0
2 years ago
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