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allochka39001 [22]
3 years ago
6

HELP FAST 20 POINTS!!

Physics
1 answer:
frez [133]3 years ago
6 0

The elements are Si, N, and Xe.

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I'm in  my lab, writing an essay about the properties of Bose Einstein Condensate. I forgot the formula of producing the condens
Artyom0805 [142]
This is a big looking question for school and for 5 points.It seems to relate to superfluidity in helium III and helium IV and something called the "lambda" point. Though I can't do it justice yet and here, it looks as though i can find tis in "Heat and Thermodynamics", Mark W Zemansky ...If rho is the density of helium II, rhon the density of the normal part, and rhoz the density of the superfluid part rho=rhon+rhoz.At the lambda point, all the atoms are normal and rhon/rho = 1, whereas at absolute zero all the atoms are superfluid and rhon/rho=0.Best I can do with the info and point available ..ps, I think that both Bose and Einstein were nobel prize winners, and the word "Boson" is in honour of the, I believe, Indian physicist Bose. It is a very interesting question, and I can in no way do it justice here.
7 0
4 years ago
How do Leeuwenhoek’s observations of animalcules compare to Hooke’s observations of cells in the cork?
fomenos

Answer:

Robert Hooke

Was the first to use the word "cell"

Observed cork cells

Anton van Leeuwenhoek

Observed "animalcules"

Used polished lens .

Explanation:

Anton van Leeuwenhoek is known as father of microbiology. He is credited to improve the quality of lens in microscope. His first observation of organisms called animalcules.

He is credited to have build microscope that could get magnified by 200 times. He used word animalcules for small organisms from pond water when first observed in microscope. He discovered protozoa and named it animalcules".

Robert Hooke is famed for discovering cell from a cork of plant. He observed a compartment or honey comb like divisions when observed these cork cells under the microscope and named it cell. He was only able to see the cell wall as the cork cells are dead cells.

8 0
3 years ago
A 40-W lightbulb is 1.7 m from a screen. What is the intensity of light incident on the screen? Assume that a lightbulb emits ra
Sonja [21]

Answer:

Intensity, I=1.101\ W/m^2

Explanation:

Power of the light bulb, P  = 40 W

Distance from screen, r = 1.7 m

Let I is the intensity of light incident on the screen. The power acting per unit area is called the intensity of the light. Its formula is given by :

I=\dfrac{P}{A}

I=\dfrac{P}{4\pi r^2}

I=\dfrac{40\ W}{4\pi (1.7\ m)^2}

I=1.101\ W/m^2

So, the intensity of light is 1.101\ W/m^2.

6 0
4 years ago
(b) The output current of the generator is 2.0A. The output potential difference (p.d.) of the
Luden [163]

Answer:

P = 22 watts

Explanation:

Given that,

The output power of the generator = 2 a

The output potential difference = 11 V

We need to find the output power of the generator. The formula for the output power is given by :

P=V\times I\\\\P=11\times 2\\\\P=22\ W

So, the output power of the generator is equal to 22 Watts.

8 0
3 years ago
The triceps muscle in the back of the upper arm is primarily used to extend the forearm. Suppose this muscle in a professional b
taurus [48]

Answer:

I = 0.483 kgm^2

Explanation:

To know what is the moment of inertia I of the boxer's forearm you use the following formula:

\tau=I\alpha  (1)

τ: torque exerted by the forearm

I: moment of inertia

α: angular acceleration = 125 rad/s^2

You calculate the torque by using the information about the force (1.95*10^3 N) and the lever arm (3.1 cm = 0.031m)

\tau=Fr=(1.95*10^3N)(0.031m)=60.45J

Next, you replace this value of τ in the equation (1) and solve for I:

I=\frac{\tau}{\alpha}=\frac{60.45Kgm^2/s ^2}{125rad/s^2}=0.483 kgm^2

hence, the moment of inertia of the forearm is 0.483 kgm^2

8 0
3 years ago
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