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2 years ago

What is the resistance of a 20.0-meter-long

Physics

2 answers:

irina [24]2 years ago

4 0

Answer:

Option (2)

Explanation:

The resistance of a conductor is directly proportional to the length of the conductor and inversely proportional to the area of the conductor. The formula for the resistance is given by

$R = \rho \frac{l}{a}$

Where, ρ is the resistivity of tungsten, l be the length of tungsten and a be the area of cross section.

The value of resistivity for tungsten is 5.6 x 10^-8 ohm metre.

$R = 5.6\times 10^{-8} \times \frac{20}{10^{-4}}$

$R = 1.12 \times 10^{-2} Ohm$

IgorC [24]2 years ago

3 0

I'm pretty sure it's 8, I could be wrong though

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anastassius [24]

Answer:

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Explanation:

Hi!

The formula that you will want to use to solve this question is:

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g --> acceleration due to gravity (9.8m/s^2)

since we know that the mass of the bob at the end of the pendulum does not affect the period of the pendulum, we can go ahead and ignore that bit of information (unless, of course, the weight causes the pendulum to stretch)

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*Note*

- I used 3.14 to pi, if you need to use a different value for pi (a longer version, etc) your answer will be slightly different

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