What is the resistance of a 20.0-meter-long
2 answers:
Answer:
Option (2)
Explanation:
The resistance of a conductor is directly proportional to the length of the conductor and inversely proportional to the area of the conductor. The formula for the resistance is given by
Where, ρ is the resistivity of tungsten, l be the length of tungsten and a be the area of cross section.
The value of resistivity for tungsten is 5.6 x 10^-8 ohm metre.
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Answer:
a) 8.99*10³ V b) 4.5*10⁻² J c) 0 d) 0
Explanation:
a)
- The electrostatic potential V, is the work done per unit charge, by the electrostatic force, producing a displacement d from infinity (assumed to be the reference zero level).
- For a point charge, it can be expressed as follows:
- As the electrostatic force is linear with the charge (it is raised to first power), we can apply superposition principle.
- This means that the total potential at a given point, is just the sum of the individual potentials due to the different charges, as if the others were not there.
- In our case, due to symmetry, the potential, at any corner of the triangle, is just the double of the potential due to the charge located at any other corner, as follows:
- The potential at point C is 8.99*10³ V
b)
- The work required to bring a positive charge of 5μC from infinity to the point C, is just the product of the potential at this point times the charge, as follows:
- The work needed is 0.045 J.
c)
- If we replace one of the charges creating the potential at the point C, by one of the same magnitude, but opposite sign, we will have the following equation:
- This means that the potential due to both charges is 0, at point C.
d)
- If the potential at point C is 0, assuming that at infinity V=0 also, we conclude that there is no work required to bring the charge of 5μC from infinity to the point C, as no potential difference exists between both points.
Answer:
- centroid: (x, y) = (81.25 mm, 137.5 mm)
- I = 8719.31 mm^2 for unit mass
Explanation:
Finding the desired measures requires we know a differential of area. That, in turn, requires we have a way to describe a differential of area. Here, we choose to use a vertical slice, which requires we know the area boundaries as a function of x.
The upper boundary is a line with a slope of 125/156.25 = 0.8, and a y-intercept of 125. That is, ...
y1 = 0.8x +125
The lower boundary is given in terms of y, but we can solve for y to find ...
100x = y^2
y2 = 10√x
Then our differential of area is ...
dA = (y1 -y2)dx
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The centroid is found by computing the first moment about the x- and y-axes, and dividing those values by the area of the figure.
The area will be ...
The y-coordinate of the centroid is ...
Similarly, the x-coordinate is ...
That is, centroid coordinates are (x, y) = (81.25, 137.5) mm.
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The moment of inertia is the second moment of the area. If we normalize by the "mass" (area), then the integral looks a lot like the one for , but multiplies dA by x^2 instead of x.
The attachment shows that value to be ...
I ≈ 8719.31 mm^2 (normalized by area)
The area is 16276.0416667 mm^2, if you want to "un-normalize" the moment of inertia.
The electric field created by Q at the position of q is .
The given parameters:
- <em>Magnitude of charge, = q</em>
- <em>Spherical charge, = Q</em>
- <em>Force experienced by both charges, = F</em>
The electric field created by Q at the position of q is calculated as follows;
where;
- <em>E is the magnitude of electric field strength </em>
- <em>F is the force experienced by both charges</em>
- <em>Q is the charge</em>
Thus, the electric field created by Q at the position of q is .
Learn more about electric field here: brainly.com/question/14372078