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Diano4ka-milaya [45]
3 years ago
15

Do the lands in our

Engineering
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

sheosjos widhoe window

Explanation:

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What did Brother Guy say when he was showing all the pictures of scientists? (the basic point he was making)
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Hopefully the other person helps you I’ll come back to see but I can’t right now
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A global resources company uses data-intensive, cloud-based simulation software, but users in remote locations find that the res
lakkis [162]

The type of technology illustrated in the given example is called; Edge Computing

We are told that;

- Company uses data-intensive, cloud-based simulation software

- Company decides to deploy multiple instances of the application in locations closer to the end users due to the fact that users in remote locations complained of lack of responsiveness.

  • Now, the type of technology illustrated from the solution the company is trying to perform is called Edge Computing.

  • This is because Edge Computing fundamentally is a type of technology that is used to bring computation and data storage closer to the user devices that collects them instead of depending on a central location that may be thousands of kilometers away.

Now, the edge computing technology is usually done to ensure that real-time data does not suffer from latency issues that can affect the performance of applications.

Read more on edge computing at;brainly.com/question/23858023

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2 years ago
Steam undergoes an isentropic compression in an insulated piston–cylinder assembly from an initial state where T1 5 1208C, p1 5
balu736 [363]

Answer:

temperature T2 = 826.9°C

\frac{W}{m} = -1142.7 kJ/kg

Explanation:

given data

initial state temperature = 120°C

final state pressure p1 = 1 bar

pressure p2 =  100 bar

solution

we use here super heated water table A6 that is

specific internal energy u1 = 2537.3 kJ/kg

specific entropy s1 = 7.4668 kJ/kg.K

and

here specific entropy stage 1 = stage 2

so for specific entropy and pressure 100 bar

specific internal energy u2 = 3680 kJ/kg

and temperature T2 = 826.9°C

so here now we get specific work of steam is

ΔU = -W     ...........1

m ( u1 - u2) = W

\frac{W}{m} = u1 - u2

\frac{W}{m} = 2537.3 - 3680

\frac{W}{m} = -1142.7 kJ/kg

3 0
3 years ago
Which of the following should NOT be included in an emergency kit?
Jet001 [13]

Answer:

Pistol

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3 years ago
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g A food department is kept at -12oC by a refrigerator in an environment at 30oC. The total heat gain to the food department is
boyakko [2]

Answer:

a) \dot W = 0.417\,kW, b) COP_{R} = 2.198, c) Irreversible.

Explanation:

a) The power input required by the refrigerator is:

\dot W = \dot Q_{H} - \dot Q_{L}

\dot W = \left(4800\,\frac{kJ}{h} - 3300\,\frac{kJ}{h}\right)\cdot \left(\frac{1}{3600} \,\frac{h}{s} \right)

\dot W = 0.417\,kW

b) The Coefficient of Performance of the refrigerator is:

COP_{R} = \frac{\dot Q_{L}}{\dot W}

COP_{R} = \frac{3300\,\frac{kJ}{h} }{(0.417\,kW)\cdot \left(3600\,\frac{s}{h} \right)}

COP_{R} = 2.198

c) The maximum ideal Coefficient of Performance of the refrigeration is given by the inverse Carnot's Cycle:

COP_{R,ideal} = \frac{T_{L}}{T_{H}-T_{L}}

COP_{R,ideal} = \frac{261.15\,K}{303.15\,K - 261.15\,K}

COP_{R,ideal} = 6.218

The refrigeration cycle is irreversible, as COP_{R} < COP_{R,ideal}.

3 0
3 years ago
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