Answer:
Given that
Mass flow rate ,m=2.3 kg/s
T₁=450 K
P₁=350 KPa
C₁=3 m/s
T₂=300 K
C₂=460 m/s
Cp=1.011 KJ/kg.k
For ideal gas
P V = m R T
P = ρ RT


ρ₁=2.71 kg/m³
mass flow rate
m= ρ₁A₁C₁
2.3 = 2.71 x A₁ x 3
A₁=0.28 m²
Now from first law for open system

For ideal gas
Δh = CpΔT
by putting the values


Q= - 45.49 KJ/kg
Q =- m x 45.49 KW
Q= - 104.67 KW
Negative sign indicates that heat transfer from air to surrounding
Answer:

Explanation:
The model for the turbine can be derived by means of the First Law of Thermodynamics:
![-\dot Q_{out}-\dot W_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right] =0](https://tex.z-dn.net/?f=-%5Cdot%20Q_%7Bout%7D-%5Cdot%20W_%7Bout%7D%20%2B%5Cdot%20m%20%5Ccdot%20%5Cleft%5B%28h_%7Bin%7D-h_%7Bout%7D%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%28v_%7Bin%7D%5E%7B2%7D-v_%7Bout%7D%5E%7B2%7D%29%20%2B%20g%5Ccdot%20%28z_%7Bin%7D-z_%7Bout%7D%29%5Cright%5D%20%3D0)
The work produced by the turbine is:
![\dot W_{out}=-\dot Q_{out} +\dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) + g\cdot (z_{in}-z_{out})\right]](https://tex.z-dn.net/?f=%5Cdot%20W_%7Bout%7D%3D-%5Cdot%20Q_%7Bout%7D%20%2B%5Cdot%20m%20%5Ccdot%20%5Cleft%5B%28h_%7Bin%7D-h_%7Bout%7D%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%28v_%7Bin%7D%5E%7B2%7D-v_%7Bout%7D%5E%7B2%7D%29%20%2B%20g%5Ccdot%20%28z_%7Bin%7D-z_%7Bout%7D%29%5Cright%5D)
The mass flow and heat transfer rates are, respectively:




Finally:


Answer:
(Have a nice day)
¶Emma Jess¶
Explanation:
Extremly toxic substances;
£Chrimium
£ Nickel
£ Aresenic
£ Asbestose
£ Magnesium
£ Sillica
£ Beryllium
£ Cadmium
£ Nitrogen
£ Oxides
£ Phosgene
£ Acrolein
£ Carbon monoxide
£ Fluorine compounds
£ Cobalt
£ Copper
£ Lead
£ Ozon
£ Selenium
£ Zinc