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CaHeK987 [17]
3 years ago
11

jimmy had 8 boxes with 3 cars in each box. if jimmy wanted to give each of his 4 friends an equal number of cars, how many cars

would each friend get?
Mathematics
2 answers:
ollegr [7]3 years ago
6 0
8 x 3= 24
23 dived by 4= 6
damaskus [11]3 years ago
5 0
8x3=24
24/4=6
so each friend gets 6 cars
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Answer:

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Step-by-step explanation:

a)

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C(a,b) \Rightarrow C(4,-3) \:the\:radius\:is\:r=\sqrt{68} \Rightarrow r=2\sqrt{17}

b) Using the previous example to show this:

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(x-a)(x -c) + (y -b)(y-d) = 0

We are indeed, naming "a" and "b", the coordinates of (a, b) of the first endpoint and "b" and "d" the second endpoint as well.Id est, D (2, 5) and B (6,-11).

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So yes, the equation of the circle can be written as

(x-a)(x -c) + (y -b)(y-d) = 0

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d_{AC}=d_{BC}=R

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Gwar [14]

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Step-by-step explanation:

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Step-by-step explanation:

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