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3 years ago

12

Need help on my math only have today till I turn int tomorrow

1 answer:

Aneli [31]3 years ago

6 0

Hope this helps explain what was needed to be solved! :)

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What is 9/10 - 11/12

kenny6666 [7]

9/10 - 11/12
Multiply both sides to find a common denominator in this case it’s 60
54/60 - 55/60
Then the answer would be -1/60

3 0

4 years ago

there are about 1.5 grams of fat in 1 tabespoon of humus.how many grams of fat are in 2 1/2 cups of hummus ?

Kipish [7]

We'll first we need to know the in 1 cup there is 16 tablespoon.
so we could multiply we need 2 1/2 cup so that is 16 (1cup) + 16 (1cup) +8 (1/2 cup)= 40 tablespoons... and 1 tablespoon is 1.5 grams of fat then we multiply 40 times 1.5 .... This is equal to 60 grams fat
So there is 60 grams of fat in 2 1/5 cups of hummus.

6 0

4 years ago

the angle of elevation of a top of a tree from a certain point on the ground is 45 degree. if the tree is 15 meters high,how is

Sphinxa [80]

Answer:

15m

Step-by-step explanation:

tan° = opposite/ adjacent

tan45 = 15/x

1 = 15/x

and = 15

6 0

3 years ago

In a company 37% of the 1500 employees are females work out the number of males in the company

kondaur [170]

100-37=63
0.63 x 1500 = 945
Answer= 945 male workers

8 0

3 years ago

Read 2 more answers

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago