<h3>(-3j²k³)²(2j²k)³</h3>
(-3j²k³)²(2j²k)³ = <em>When a power is raised to a power the exponents have to be multiplied.</em>
= (-3²j⁽²*²⁾k⁽³*²⁾)(2³j⁽²*³⁾k³) = <em>We can take out the constants</em>
= (9)(8)(j⁴k⁶)(j⁶k³) = <em>We can group the same variables</em>
= 72(j⁴j⁶)(k⁶k³) = <em>When multiplying two powers that have the same base, you have to add the exponents.</em>
= 72 j⁽⁴⁺⁶⁾k⁽⁶⁺³⁾ = 72j¹⁰k⁹
Answer = 72j¹⁰k⁹
Hope this helps!
Answer:
Line s and Line t are parallel.
Step-by-step explanation:
Now, we know that angles 1 and 2 are congruent, because they have the same angle measures. Now, looking at their positions, we can see that they are alternate exterior angles.
By the converse of the Alternate Exterior Angle, (I do not remember exactly how the theorem went) if two lines are cut by a transversal and have congruent alternate exterior angles, then the lines are parallel. Using this theorem, we can find that lines s and t are parallel, because they are cut by a transversal and their alternate exterior angles are congruent.
I hope you find my answer and explanation to be helpful. Happy studying.
Answer:
Table C
Step-by-step explanation:
Now where is my Brainliest XD
