Answer:
(x-2)(x-26)
Step-by-step explanation:
x^2-2x-26x+52
x(x-2)-26(x-2)
(x-2)(x-26)
Answer: 297 i believe i am a little rusty at this
Sometimes when you're given dimensions that differ by some amount, it is easier to work with their average value. Let x represent the average of length and width of the rectangle. The length and width differ from this average value by 1.5 m. Then the area is
.. (x +1.5)*(x -1.5) = 154
.. x^2 -2.25 = 154
.. x^2 = 156.25
.. x = 12.5
The width is 1.5 m shorter than this, or 11 m.
_____
Solved in the conventional way, you are looking for factors of 154 that differ by 3. This means you have to find the factors of 154, or use the quadratic formula.
.. 154 = 1*154 = 2*77 = 7*22 = 11*14 (the pair we want)
Once you have the factorization of 154, you have the answer. No equations are necessary, really.
Answer: shifted left 6 units, down 4 units, and reflected over the x-axis
<u>Step-by-step explanation:</u>
The vertex form of a quadratic equation is: y = a(x - h)² + k where
- "a" is the vertical stretch
- -a is a reflection over the x-axis (+a = U-shape), -a = ∩-shape)
- (h, k) is the vertex
- h is the horizontal shift (positive = right, negative = left)
- k is the vertical shift (positive = up, negative = down)
Given: Vertex (h, k) = (-6, -4)
Parabola is ∩-shaped so "a" is negative
Next points from vertex are 1 down 1 right and 1 down 1 left --> a = -1
Input a = -1, h = -6, k = -4 into the Vertex form:
y = -(x + 6)² - 4
a = -1: reflected over the x-axis
h = -6: shifted left 6 units
k = -4: shifted down 4 units