If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
what do you mean by graph
Step-by-step explanation:
Answer:
115 days, untill she has payed her mom the full amount. plz pick me as the brainleist! XD
Step-by-step explanation:
Answer: 74.25 Php, 4.45kg, 182 Php, 30 People, and 315 Php
Step-by-step explanation:
1. 200-125.75= 74.25 Php
2. 1.5+1.7+1.25=4.45kg
3. 45.50*4 = 182 Php
4. 45/1.5 = 30 People
5. 35.00*9 = 315 Php
Answer:(0.6,10.6) after 8 seconds.
Step-by-step explanation:
