Answer:
All given option
Step-by-step explanation:
the answer is All given option hahahahajahahahahahahajaja
Answer:

Step-by-step explanation:
Hello There!
The angle labeled 6x is a right angle
If an angle is formed using the diameter of a circle then the opposite angle of that side is a right angle
So 6x = 90
isolate the variable
divide each side by 6
90/6= 15
6x/6=x
we're left with x = 15
If the pentagon is rotated 360° about the origin, that means the new figure will be exactly in the same position as the original image, because a rotation of 360° about the origin doesn't change the figure position or orientation.
So, if the vertex was located at (10, -8), the new figure will also have a vertex located at (10, -8).
Therefore the correct option is the fourth one.
We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of
and 

Finally, we can use the Pythagorean Theorem to find the length of
:





Answer:
How to Graph a Linear Inequality
First, graph the "equals" line, then shade in the correct area.
There are three steps:
1.) Rearrange the equation so "y" is on the left and everything else on the right.
2.) Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
4.) Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).
Hope This Helps! Have A Nice Day!!