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IrinaVladis [17]
3 years ago
6

An art collector buys a replica of a famous sculpture. The replica has exactly the same shape as the original but is smaller. Th

e replica is 18 cm tall, and the the
original sculpture is 30 cm tall. If 189 cm of bronze was needed to make the replica, how much bronze was needed to make the original sculpture?
​
Mathematics
2 answers:
Luba_88 [7]3 years ago
4 0

Answer:

The answer is 315 cm of bronze

Step-by-step explanation:

yKpoI14uk [10]3 years ago
3 0

Answer:

315cm

Step-by-step explanation:

For this, we need to set up a proportion.

18/189=30/x

Cross multiply.

18x=189*30

18x=5670

Divide both sides by 18.

x=315

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atroni [7]
Equations are: 4x + 2y = 6
x - y = 3
Multiply 2nd equation by 2, 
2x - 2y = 6
Add both the equations,
6x = 12
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In short, Your Answer would be 2

Hope this helps!
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3 years ago
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ki77a [65]

Answer:

17

Step-by-step explanation:

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4 years ago
What restrictions must be made on x, y, and z so that the triple (x, y, z) will represent a point on the y axis? On the z axis?
Aneli [31]

Answer:i) The point on y-axis is (0,y,0)

            ii) The point on z-axis is (0,0,z)

            iii)  The point on x z plane is (x,o,z)

            iv) The point on y z plane is (0,y,z)

Step-by-step explanation:

Explanation:-

i) For every point on x-axis, y-co-ordinate is zero and z- co-ordinate is zero

i .e., y=0 and z=0

The point on x-axis is (x,0,0)

ii) For every point on y-axis, x-co-ordinate is zero and z- co-ordinate is zero

i .e., x=0 and z=0

The point on y-axis is (0,y,0)

iii) For every point on z-axis, x-co-ordinate is zero and y- co-ordinate is zero

i .e., x=0 and y=0

The point on z-axis is (0,0,z)

iv)  For every point on X Z plane then Y=0

The point on x z plane is (x,o,z)

v) For every point on Y Z plane then X=0

The point on yz plane is (0,y,z)

vi) For every point on X Y plane then Z=0

The point on x y plane is (x,y,0)

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MAXImum [283]

You basically can solve for hypothetical sides of this triangle using sohcahtoa backwards. In the first column, it says that adjacent/hypotenuse = .97. We can come up with two values that satisfy this equation. For example, the adjacent side can be .97 and the hypotenuse can be 1. These values don't matter as long as adjacent/hypotenuse is .97.

The second column tells us that opposite/hypotenuse = .26. At this point, we already have a hypothetical hypotenuse with a length of 1, so we can plug that in and find that the opposite side of C is .26.

Now that we have a hypothetical triangle with sides .97, .26, and 1, you can use these values as well as sohcahtoa to solve for the rest with respect to angle A. Keep in mind that the line AB is .26 and that the line BC is .97.

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