381 meters because you divide 1250 by 3.281 and you get 381 meters
Equation: 50+15x=200
solution: x= 10
it would take him 10 weeks to purchase the bike he wants.
Answer:
4y = 6x + 40
Step-by-step explanation:
The general equation of a straight line is y = mx + b
m is the slope and b is the y-intercept
let us write both equations in this form;
we have this as;
6y = -4x + 1
y = -4x/6 + 1/6
and;
2x + 3y = 18
3y = -2x + 18
y = -2x/3 + 6
So firstly we want to find an equation that is perpendicular to the first
When two lines are perpendicular, their slopes has a product of -1
The slope of the first line is -4/6
let the slope of the line we want be m
As per they are perpendicular;
-4/6 * m = -1
-4m/6 = -1
-4m = -6
m = 6/4
So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6
we can choose 10
and we have the equation as:
y = 6x/4 + 10
multiply through by 4
4y = 6x + 40
Answer:
A. 34 miles
Step-by-step explanation:
First, you want to subtract $3.50 from $60. Now you have $56.50. Now you want to divide that by $1.65, to see how many miles you can achieve with your price limit. So, now you have a grand total of 34.24. You round that, and you finally have your answer.
The answer to this problem is A. 34 miles
Answer: The least score she can get on her next test is 455 points.
Step-by-step explanation: From the available information, her current mean score is 88%, and that was achieved from a total of 5 tests. Hence, her mean score was computed as follows;
Mean = (Summation of data)/observed data
Where the observed data is 5 and the mean is 88. Therefore the mean can now be expressed as,
88 = Summation of data/5
By cross multiplication we now have
88 x 5 = Summation of data
440 = Summation of data.
So, if she wants to raise her mean score on her next test to 91%, her least possible score would be derived as
91 = (Summation of data)/5
By cross multiplication we now have
91 x5 = Summation of data
455 = Summation of data
Therefore, on her next test, she must score at least 455 points.
