Hello,
y=2xe^x
y'=2(e^x+xe^x)=2(x+1)e^x
y''=2(e^x+(x+1)e^x)=2(x+2)e^x
x |-infinite -2 0 +infinite
e^x | ++++++++++++++++++
x+2 |------------0 +++++++++++
y'' | -----------0 +++++++++++
y''<0 if x<-2
<span>The interval on which the graph is concave down is (-infinite -2[</span>
Answer:
4
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
24/6 = 4
Check by taking the third term and dividing by the second term
96/24 = 4
The common ratio is 4
Nice, already in vertex form
y=a(x-h)^2+k
(h,k) is vertex
therfor since (-3,6) is vertex
we are looking for something like
y=a(x-(-3))^2+6 simplified to
y=a(x+3)^2+6
A is ansre
Answer:
419
Step-by-step explanation:
the answer is 419 because 38+39=77+40=117+41=158+130=288+131=419
hope my math is correct =)
