All categories

2 years ago

Which of the following lists is in order from smallest to largest?

Mathematics

1 answer:

kupik [55]2 years ago

7 0

Answer:

Step-by-step explanation:

1/2 = 0.5

5/8 = 0.625

7/11 = 0.63

2/3 = 0.66

You might be interested in

In 0.57 which is the part and which is the whole

jek_recluse [69]

There is no whole number and .57 is the part...

7 0

2 years ago

Which expression is equivalent to 4(23)?

valkas [14]

Answer:

Step-by-step explanation:

Multiply 4 and 23:

4 * 23 = 92

4 0

2 years ago

104 tests is what % of 160 tests

Afina-wow [57]

160 test=100%

Therefore:

160 test------------------100%
104 test------------------ x
x=(104 test*100%) / 160 test=65%

Answer: 104 test is the 65% of 160 test

8 0

2 years ago

Pls help me on B asap

Zanzabum

Take the common denominator and divide by 3 then youll get 58

3 0

2 years ago

According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 20

Murljashka [212]

Answer:

There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1432

p = 23% = 0.23

Alpha, α = 0.05

Number of theft complaints , x = 321

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.23\\H_A: p < 0.23$

This is a one-tailed test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{321}{1432} =0.2241$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2241-0.23}{\sqrt{\frac{0.23(1-0.23)}{1432}}} = -0.5305$

Now, we calculate the p-value from the table.

P-value = 0.298

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Conclusion:

Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

5 0

2 years ago