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3 years ago

Please help asap!!!!!!!!!!!!

Mathematics

2 answers:

elena55 [62]3 years ago

7 0

Answer:

ok whatchu need help with

Step-by-step explanation:

makvit [3.9K]3 years ago

5 0

Answer:

What do you need help with?

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Nathan buys coffee and hot chocolate for his co-workers. Each cup of coffee costs $1.55 and each cup of hot chocolate costs $1.0

Sloan [31]

Answer:

he buys 6.78

Step-by-step explanation:

8 0

3 years ago

The leaves of a poison ivy plant are found in clusters of 3.One poison ivy plant has a total of 21 leaves.How many leaf clusters

Serhud [2]

21/3 = 7 total clusters of leaves

8 0

3 years ago

Am I correct if I am not please give me the right answer and I’ll give points. Thank you

STatiana [176]

the first two are correct, but the answer for c should be 125

3 0

3 years ago

Read 2 more answers

How do I find the y intercept in a fraction

Furkat [3]

ANSWER:

Both functions have the same slope

The linear equation does not have a y-intercept

The table and the grahp express an equivalent function

STEP-BY-STEP EXPLANATION:

In order to compare, we must calculate the slope of the table, knowing that the equation in its slope and intercept form is the following:

$\begin{gathered} y=mx+b \\ \text{where m is the slope and b is y-intercept} \end{gathered}$

The formula to calculate the slope is the following:

$m=\frac{y_2-y_1}{x_2-x_1}$

The points are (-6, -9/2) and (4,3), replacing:

$m=\frac{3-(-\frac{9}{2})}{4-(-6)}=\frac{3+\frac{9}{2}}{4+6}=\frac{\frac{15}{2}}{10}=\frac{15}{20}=\frac{3}{4}$

The slope is 3/4

Now, for b

x = 4

y = 3

m = 3/4

replacing:

$\begin{gathered} 3=\frac{3}{4}\cdot4+b \\ b=3-3 \\ b=0 \end{gathered}$

The equation is:

$y=\frac{3}{4}x$

Therefore, the true statements are:

• Both functions have the same slope

• The linear equation does not have a y-intercept

• The table and the grahp express an equivalent function

8 0

11 months ago

Evaluate Dx / ^ 9-8x - x2^

Solnce55 [7]

It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for $\sqrt x$ .

In that case, you want to find the antiderivative,

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}$

Complete the square in the denominator:

$9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2$

Now substitute $x+4=5\sin y$ , so that $\mathrm dx=5\cos y\,\mathrm dy$ . Then

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy$

which simplifies to

$\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy$

Now, recall that $\sqrt{x^2}=|x|$ . But we want the substitution we made to be reversible, so that

$x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)$

which implies that $-\dfrac\pi2\le y\le\dfrac\pi2$ . (This is the range of the inverse sine function.)

Under these conditions, we have $\cos y\ge0$ , which lets us reduce $\sqrt{\cos^2y}=|\cos y|=\cos y$ . Finally,

$\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C$

and back-substituting to get this in terms of $x$ yields

$\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C$

4 0

3 years ago