Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
<span>centimeter, inch, yard, meter, kilometer, mile</span>
Option A:
Solution:
Given data:
Center of the circle is (5, 3).
Radius of the circle = 4
To find the equation of the circle:
The general form of the equation of a circle in centre-radius format is
where (h, k) is the centre of the circle and r is the radius of the circle.
Substitute the given values in the equation of a circle formula:
The equation of the given circle is .
Hence Option A is the correct answer.
Answer:
y≤-1/2(x=4)+3
Step-by-step explanation: