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kifflom [539]
3 years ago
8

A double-slit interference pattern is created by two narrow slits spaced 0.21 mm apart. The distance between the first and the f

ifth minimum on a screen 61 cm behind the slits is 6.2 mm What is the wavelength of the light used in this experiment?
Physics
1 answer:
olga nikolaevna [1]3 years ago
4 0

Answer:

\lambda =533.6 nm

Explanation:

the slits spacing, d = 0.21 mm

distance of screen, D = 61 cm

The condition for minima is given as

dsin(\theta) = \left ( n+\frac{1}{2} \right )\lambda

So, first minima, n = 0

dsin(\theta_1) = \frac{1}{2}\lambda

fifth minima, n = 4

dsin(\theta_5) = \frac{9}{2}\lambda

d(sin(\theta_5) -sin(\theta_1))= 4\lambda

For small angle

d(tan(\theta_5) -tan(\theta_1))= 4\lambda

From the figure:

d(\frac{y_5}{D}-\frac{y_1}{D})= 4\lambda

\frac{d}{D} (y_5-y_1) = 4\lambda

\lambda = \frac{d}{4D} (y_5-y_1)

\lambda = \frac{0.021}{4(61)} (6.2 \times 10^{-3})

\lambda =533.6 nm

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A ball is thrown at 20 m/s from the ground upwards at an angle of elevation of 30°. How far away does it land? 35.35 m
mestny [16]

Answer:

35.35 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 20 m/s

Angle of projection (θ) = 30°

Acceleration due to gravity (g) = 9.8 m/s²

Range (R) =.?

The range (i.e how far away) of the ball can be obtained as follow:

R = u² Sine 2θ /g

R = 20² Sine (2×30) / 9.8

R = 400 Sine 60 / 9.8

R = (400 × 0866) / 9.8

R = 346.4 / 9.8

R = 35.35 m

Therefore, the range (i.e how far away) of the ball is 35.35 m

8 0
3 years ago
A violin string vibrates at 260 Hz when unfingered. At what frequency will it vibrate if it is fingered one fourth of the way do
Advocard [28]

Answer:

346.66 Hz

Explanation:

l_1 = Length of string which is unfingered = l

l_2 = Length of string which is vibrate when fingered = l-\dfrac{1}{4}l=\dfrac{3}{4}l

f_1 = Unfingered frequency = 260 Hz

f_2 = Fingered frequency

Frequency is inversely proportional to length

f=\dfrac{1}{l}

So,

\dfrac{f_1}{f_2}=\dfrac{l_2}{l_1}\\\Rightarrow \dfrac{f_1}{f_2}=\dfrac{\dfrac{3}{4}l}{l}\\\Rightarrow \dfrac{f_1}{f_2}=\dfrac{3}{4}\\\Rightarrow f_2=\dfrac{4}{3}f_1\\\Rightarrow f_2=\dfrac{4}{3}260\\\Rightarrow f_2=346.66\ Hz

The frequency of the fingered string is 346.66 Hz

3 0
2 years ago
AM radio signals have frequencies between 550 kHz and 1600 kHz (kilohertz) and travel with a speed of 3.0Ã108m/s. What are the w
Westkost [7]

Answer:

The wavelength of these signals is as follow:

  • Wavelength of 550 kHz is 545.45 m
  • Wavelength of 1600 kHz is 187.5 m

Explanation:

Given that:

Frequency = 550 kHz & 1600 kHz

Velocity = 3.0 x 10⁸ m/s

As we know that frequency is expressed by the following equation:

  • Frequency = Velocity / Wavelength ---- (1)

For 550 kHz:

The equation can be rearranged as

Wavelength = Velocity / Frequency

Wavelength = (3.0 x 10⁸ m/s) / (550 x 1000 Hz)

Wavelength = 545.45 m

For 1600 kHz:

Wavelength = Velocity / Frequency

Wavelength = (3.0 x 10⁸ m/s) / (1600 x 1000 Hz)

Wavelength = 187.5 m

5 0
3 years ago
A11) A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic fiel
vitfil [10]

Answer:

A

Explanation:

From a Solenoid we know that a magnetic fiel is always inversely proportional to lenght L or BL = constant

B= frac{\mu_0}{2R}

As I is constant

\frac{B2}{B1} = \frac{R1}{R2}

B2 = 2mT*\frac{18}{21}

B2 = 1.714mT

7 0
3 years ago
Suppose the glass paperweight has index of refraction n=1.38. a) find the value of θ for which the reflection on the vertical su
zimovet [89]

Answer:

a)θ=71.89°

b)NO

Explanation:

Given that

For glass n= 1.38

We know that for air n'=1

The angle  for total internal reflection θc given as

sin θc=n'/n

By putting the values

sin θc=n'/n

sin θc=1/1.38

θc=46.43°

n'sinθ = n sinθref

sinθref = cosθc

n'sinθ =  n cosθc

1 x sinθ =1.38 x cos 46.43°

θ=71.89°

b)

NO

8 0
3 years ago
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