Answer:
33.48 V
Explanation:
Parameters given:
Number of turns, N = 420
Magnetic field strength, B = 0.055 T
Area, A = 0.065 m²
Angular velocity, ω = 22.3 rad/s
EMF induced in a coil is given as:
EMF = -dΦ/dt
where Φ = magnetic flux
Magnetic flux, Φ, is given as:
Φ = B * N * A * cosωt
EMF = -d( B * N * A * cosωt) / dt
EMF = B * N * A * ω * sinωt
where ωt = 90°
Therefore:
EMF = 0.055 * 420 * 0.065 * 22.3 * sin90°
EMF = 33.48 V
7500J
Explanation:
Given parameters:
Weight of child = 150N
Height of lifting = 50m
Distance = 50m
Unknown:
Work done by the woman = ?
Solution:
Work done by a body is the force applied to move a body through a given distance.
Work done = Force x distance
Weight is a force impacted by the mass of a body and the gravity on it.
input the parameters:
Work done = 150 x 50 = 7500J
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Answer:
The work done on the wagon is 37 joules.
Explanation:
Given that,
The force applied by Charlie to the right, F = 37.2 N
The force applied by Sara to the left, F' = 22.4 N
We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :



Work done on the wagon is given by the product of net force and displacement. It is given by :


W = 37 Joules
So, the work done on the wagon is 37 joules. Hence, this is the required solution.