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IRISSAK [1]
3 years ago
12

Do rolling down a grassy hill has kinetic energy or potential energy

Physics
2 answers:
Ann [662]3 years ago
4 0

If you're moving, then you have kinetic energy.

If you're not at the bottom yet, then you still have
some potential energy left.

allochka39001 [22]3 years ago
3 0

Answer:

Kinetic and potential energy

Explanation: the energy starts at the top of the hill as potential energy and changes to kinetic energy as you go down the kill

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Bad White [126]

Answer:

12.5 km

Explanation:

Since 30.0 minutes is half of an hour and the average speed is 25.0 km/h we can multiply the time by the speed to find the distance travelled.

25.0km/h x 0.5 hours = 12.5 km

4 0
3 years ago
Question 9 of 10<br> How many carbon (C) atoms are in a molecule of CH,O?
Juli2301 [7.4K]

Answer:

1 molecule not shure

Explanation:

6 0
3 years ago
Read 2 more answers
A parcel has a mass of 500 g .calculate its weight (assume the gravitational field strength is 10 N/Kg
Effectus [21]

Answer:

5N

Explanation

convert grams to kg and multipy with 10 (.5 *10)=5N

5 0
3 years ago
As a mercury atom absorbs a photon of
Allisa [31]
The energy absorbed by photon is 1.24 eV.
This is the perfect answer.
8 0
2 years ago
The main purpose of an air bag is to stop a passenger during a car accident in a greater amount of time than if the air bag were
Simora [160]

Answer:

a) 45571 N  

b) 22786 N

c) 4557 N

Explanation:

  • Since the goal of the airbag is helping the person to stop after the collision in a greater time, this means that the change in momentum must finish when this is just zero.
  • In other words, the change in momentum, must be equal to the initial one, but with opposite sign.

       \Delta p = - p_{o} = -m*v = -55 kg*29m/s = -1595 kgm/s (1)

  • Now, just applying the original form of  Newton's 2nd Law, we know that this change in momentum must be equal to the impulse needed to stop the person:

       \Delta p = F* \Delta t  (2)

  • So, as we know the magnitude of Δp from (1) and we have different Δt as givens, we can get the different values of F (in magnitude) required to stop the person for each one of them, as follows:

       F_{1} = \frac{\Delta p}{\Delta t_{1}} = \frac{1595kgm/s}{0.035s} = 45571 N (3)

       F_{2} = \frac{\Delta p}{\Delta t_{2}} = \frac{1595kgm/s}{0.07s} = 22786 N (4)

       F_{3} = \frac{\Delta p}{\Delta t_{3}} = \frac{1595kgm/s}{0.35s} = 4557 N (5)

4 0
3 years ago
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