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vodomira [7]
3 years ago
6

How to find a planet’s gravitational field strength using its radius?

Physics
1 answer:
grin007 [14]3 years ago
5 0

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

g = \frac{F}{m}

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And F =\frac{GMm}{r^{2} }

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11}  \times 1}{(6.6 \times 10^{6}) ^{2} }

g = 0.977 \times 10^1= 9.77\ N

So, the gravitational field strength is approximately equal to 10 N.

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The height of the Washington Monument is measured to be 170 m on a day when its temperature is 35.0°C. What will the change in i
Alecsey [184]

Answer:

The deformation is 0.088289 m

The final height of the monument is 170-0.088289 = 169.911702 m

Explanation:

Thermal coefficient of marble varies between (5.5 - 14.1) ×10⁻⁶/K = α

So, let us take the average value

(5.5+14.1)/2 = 9.8×10⁻⁶ /K

Change in temperature = 35-(-18) = 53 K = ΔT

Original length = 170 m = L

Linear thermal expansion

\frac{\Delta L}{L} = \alpha\Delta T\\\Rightarrow \Delta L=\frac{\alpha\Delta T}{L}\\\Rightarrow \Delta L=9.8\times 10^{-6}\times 53\times 170

The deformation is 0.088289 m

The final height of the monument is 170-0.088289 = 169.911702 m (subtraction because of cooling)

4 0
3 years ago
Which sound wave-object interaction is used by animals in echolocation?
tekilochka [14]
The answer is reflection
5 0
3 years ago
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A wheel of diameter 30.0 cm starts from rest and rotates with a constant angular acceleration of 3.50 rad/s2 . At the instant th
____ [38]

Answer: The radial acceleration of a point on the rim in two ways is 13.20 m/s^2

Explanation: Please see the attachments below

5 0
3 years ago
At an amusement park, a 7.00 kg swimmer uses a water slide to enter the main pool. The swimmer starts at rest, slides without fr
telo118 [61]

Answer:

27.44 J

Explanation:

We can find the energy at the top of the slide by using the potential energy equation:

  • PE = mgh

At the top of the slide, the swimmer has 0 kinetic energy and maximum potential energy.

The swimmer's mass is given as 7.00 kg.

The acceleration due to gravity is 9.8 m/s².

The (vertical) height of the water slide is 0.40 m.

Substitute these values into the potential energy equation:

  • PE = (7.00)(9.8)(0.40)
  • PE = 27.44

Since there is 0 kinetic energy at the top of the slide, the total energy present is the swimmer's potential energy.

Therefore, the answer is 27.44 J of energy when the swimmer is at the top of the slide.

6 0
3 years ago
What happens to the reaction 2 N O 2 in equilibrium with N 2 O 4 plus 57.3 kilojoules when the temperature of the reaction is in
Burka [1]

Answer:

More reactant forms.

Explanation:

Given reaction is,

2NO_{2}⇒N_{2} O_{4}+57.3 KiloJoulesper mole

This is an Exothermic Reaction,(ΔE=-57.3KJper mole)

We know the equilibrium point of all Exothermic reactions moves leftward and more reactant is formed at the equilibrium.

<u>Reason:</u>

As heat is being produced in the reaction the additional heat(57.3KJpermole) can be <u>thought of as a product</u> of the reaction.

So,if you increase the temperature ,you provide heat energy,

(in other words heat energy is given) and hence the concentration of the products increases.

So, with respect to LeChateliers Principle,

As the concentration of products is increased by external means,more of the reactants are produced at the equilibrium of the reaction.

Therefore amount of reactants increases as <u>more reactant forms.</u>

3 0
3 years ago
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