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vodomira [7]
3 years ago
6

How to find a planet’s gravitational field strength using its radius?

Physics
1 answer:
grin007 [14]3 years ago
5 0

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

g = \frac{F}{m}

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And F =\frac{GMm}{r^{2} }

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11}  \times 1}{(6.6 \times 10^{6}) ^{2} }

g = 0.977 \times 10^1= 9.77\ N

So, the gravitational field strength is approximately equal to 10 N.

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The average speed during any time interval is equal to the total distance of travel divided by the total time. Let d represent t
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Answer:

Average speed = 3.63 m/s

Explanation:

The average speed during any time interval is equal to the total distance travelled divided by the total time.

That is,

Average speed = distance/ time

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Let t1 be the time for which she has the higher speed of 5.15 m/s. Therefore,

5.15 = d/t1.

Make d the subject of formula

d = 5.15t1

Let t2 represent the longer time for the return trip at 2.80 m/s . That is,

2.80 = d/t2.

Then the times are t1 = d/5.15 5 and

t2 = d/2.80.

The average speed vavg is given by the following equation.

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Avg speed = d + d/t1 + t2

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Total time = d/5.15 + d/2.80

Total time = (2.8d + 5.15d)/14.42

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Total time = 0.55d

Substitute total distance and time into the formula above.

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7 0
3 years ago
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That's two different things it depends on:

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AND
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Here's what I have in mind for an experiment to show those two dependencies:

-- a closed box with a wall down the middle, separating it into two closed sections;

-- a little round hole in the east outer wall, another one in the west outer wall,
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So that if you wanted to, you could carefully stick a soda straw straight into one side,
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-- a tiny fan that blows air through a tube into the hole in one outer wall.

<u>Experiment A:</u>

-- Pour 1 ounce of water into a narrow dish, with a small surface area.
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-- Count the amount of time it takes for the 1 ounce of water to completely evaporate.
=============================
-- Pour 1 ounce of water into a wide dish, with a large surface area.
-- Set the dish in the second section of the box ... the one the air passes through
just before it leaves the box.
-- Start the fan.
-- Count the amount of time it takes for the 1 ounce of water to completely evaporate.
=============================
<span><em>Show that the 1 ounce of water evaporated faster </em>
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<u>Experiment B:</u>

-- Again, pour 1 ounce of water into the wide dish with the large surface area.
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-- Start the fan.
-- Count the amount of time it takes for the 1 ounce of water to completely evaporate.
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<em>Show that it took longer to evaporate when the air </em>
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What will happen when you slide the sponges in different directions?
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Transform boundary

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