Answer:
Step-by-step explanation:
First confirm that x = 1 is one of the zeros.
f(1) = 2(1)^3 - 14(1)^2 + 38(1) - 26
f(1) = 2 - 14 + 38 - 26
f(1) = -12 + 38 = + 26
f(1) = 26 - 26
f(1) = 0
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next perform a long division
x -1 || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26
2x^3 - 2x^2
===========
-12x^2 + 28x
-12x^2 +12x
==========
26x -26
26x - 26
========
0
Now you can factor 2x^2 - 12x + 26
2(x^2 - 6x + 13)
The discriminate of the quadratic is negative. (36 - 4*1*13) = - 16
So you are going to get a complex result.
x = -(-6) +/- sqrt(-16)
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2
x = 3 +/- 2i
f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)
The zeros are
1
3 +/- 2i
If you throw a die, this is what you could get:
1, 2, 3, 4, 5 or 6.
--------------
Odd Numbers: 1, 3, 5
Numbers less than Three: 1, 2
---------------
Possibility of getting 1, 2, 3 or 5:
4/6 which translates into 2/3.
---------------
Answer:
2/3
not understanding what you are saying?
Answer:
i think the anser is 150 sorry if im wrong
Step-by-step explanation:
2x2x2= 8
3x3= 9
8+9= 17x8= 136+14= 150
