How can you tell if a division problem as a remainder without dividing
2 answers:
-- Take the number to be divided.
-- Find all of its factors.
-- If you divide it by one of its factors, then there will be no remainder.
-- If you divide it by any other number, then there will be a remainder.
If there's factors there is no remainders but if there no factors is then is has to have a remainder its like the opposite
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Hello,
![\sqrt{x} - \sqrt{y} = (\sqrt[4]{x}+ \sqrt[4]{y} )( \sqrt[4]{x} - \sqrt[4]{y} )=72\\\\ \sqrt[4]{x}- \sqrt[4]{y}=6\\\\ (\sqrt[4]{x}+ \sqrt[4]{y})*6=72\\\\ \sqrt[4]{x}+ \sqrt[4]{y}=12 \\ \sqrt[4]{x}- \sqrt[4]{y}=6 \\\\ 2 \sqrt[4]{x}=18==\textgreater\sqrt[4]{x}=9==\textgreater\ x=6561\\ 2 \sqrt[4]{y}=6==\textgreater\sqrt[4]{y}=3==\textgreater\ y=81\\ ](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20-%20%5Csqrt%7By%7D%20%3D%20%28%5Csqrt%5B4%5D%7Bx%7D%2B%20%5Csqrt%5B4%5D%7By%7D%20%29%28%20%5Csqrt%5B4%5D%7Bx%7D%20-%20%5Csqrt%5B4%5D%7By%7D%20%29%3D72%5C%5C%5C%5C%0A%5Csqrt%5B4%5D%7Bx%7D-%20%5Csqrt%5B4%5D%7By%7D%3D6%5C%5C%5C%5C%0A%28%5Csqrt%5B4%5D%7Bx%7D%2B%20%5Csqrt%5B4%5D%7By%7D%29%2A6%3D72%5C%5C%5C%5C%0A%5Csqrt%5B4%5D%7Bx%7D%2B%20%5Csqrt%5B4%5D%7By%7D%3D12%20%5C%5C%20%0A%5Csqrt%5B4%5D%7Bx%7D-%20%5Csqrt%5B4%5D%7By%7D%3D6%20%5C%5C%5C%5C%0A2%20%5Csqrt%5B4%5D%7Bx%7D%3D18%3D%3D%5Ctextgreater%5Csqrt%5B4%5D%7Bx%7D%3D9%3D%3D%5Ctextgreater%5C%20x%3D6561%5C%5C%0A2%20%5Csqrt%5B4%5D%7By%7D%3D6%3D%3D%5Ctextgreater%5Csqrt%5B4%5D%7By%7D%3D3%3D%3D%5Ctextgreater%5C%20y%3D81%5C%5C%0A%0A%0A%20)
Proof:
The answer is 29 I put it in my scientific calculator
X = 3
20 characterssssssssssss
Answer:
1,113.87
Step-by-step explanation: Ps it was a joke man
Answer:
look at the picture i have sent