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NemiM [27]
3 years ago
9

Which substance is a heterogeneous mixture?

Physics
1 answer:
Alex3 years ago
3 0

Answer:

Granola Bar

heterogeneous:  Makeup of the object can be separated:  In this case; oats, nuts, fruit etc.

Explanation:

All the other options are homogenous.  

Cheddar cheese:  consistent make-up

Drinking water:  H20 plus sanitizers like chlorine but is not separable

Clean air:  Oxygen and nitrogen mixture

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Answer both and i’ll venmo u rn if ur right pls pls
Masteriza [31]

Answer:

2.5

Explanation:

25-22.5n= will give you 2.5

5 0
3 years ago
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Two charged objects have a repulsive force of 0.040 N. If the distance separating the objects is doubled, then what is the new f
Georgia [21]

Answer:

Two charged objects have a repulsive force of 0.080 N. If the charge of both of the objects is doubled, then what is the new force? Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of both objects is doubled, then the force will become four times greater.

Explanation:

hope this helps

7 0
2 years ago
The pressure of a gas is reduced from 1200.0 mm hg to 850.0 mm hg as the volume of its container is increased by moving a piston
Kamila [148]
From gas laws:
\frac{PV}{T} = Constant

Therefore,
\frac{ P_{1}  V_{1} }{ T_{1} } =  \frac{ P_{2}  V_{2} }{ T_{2} }

P1 = 1200 mm
V1 = 85 ml
T1 = 90°C = 363.15 K
P2 = 850 mm
V2 = 350 ml
T2 = ?

Substituting;
T_{2} =  \frac{ P_{2}  V_{2}  T_{1} }{ P^{1}  V^{1} } =  \frac{850*350*363.15}{1200*85} = 1059.19 K = 786.04 °C
8 0
3 years ago
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The mineral quartz has a chemical formula of SiO2. What is the formal name<br> for this compound?
lana66690 [7]

Answer:

Silicon Dioxide

3 0
2 years ago
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A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
nlexa [21]

To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

\epsilon = -NAcos\theta \frac{dB}{dt}

\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

At time t = 5.71s,  Induced emf is,

\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

\epsilon = 10.9V

Therefore the magnitude of the induced emf is 10.9V

4 0
3 years ago
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