Answer:
2. You must be able to precisely measure variations in the star's brightness with time.
5. As seen from Earth, the planet's orbit must be seen nearly edge–on (in the plane of our line-of-sight).
6. You must repeatedly obtain spectra of the star that the planet orbits.
Explanation:
The transit method is a very important and effective tool for discovering new exoplanets (the planets orbiting other stars out of the solar system). In this method the stars are observed for a long duration. When the exoplanet will cross in front of theses stars as seen from Earth, the brightness of the star will dip. To observe this dip following conditions must be met:
1. The orbit of the planet should be co-planar with the plane of our line of sight. Then only its transition can be observed.
2. The brightness of the star must be observed precisely as the period of transit can be less than a second as seen from Earth. Also the dip in brightness depends on the size of the planet. If the planet is not that big the intensity dip will be very less.
3. The spectrum of the star needs to be studied and observe during the transit and normally to find out the details about the planets.
4. Also, the orbital period should be less than the period of observation for the transit to occur at least once.
Answer:
gravitational potential energy:
GPE = m g h
kinetic energy:
KE = 1/2 m v^2
Answer:
W=1055N
Explanation:
In order to solve this problem, we must first do a drawing of the situation so we can visualize theh problem better. (See attached picture)
In this problem, we will ignore the board's weight. As we can see in the free body diagram of the board, there are only three forces acting on the system and we can say the system is in vertical equilibrium, so from this we can say that:
so we can do the sum now:
when solving for the Weight W, we get:
and now we can substitute the given data, so we get:
W=410N+645N
W=1055N
Answer:bowling ball has greater kinetic energy
Explanation:
Kinetic energy of bowling ball:
mass=m=5kg
Velocity=v=6m/s
Kinetic energy =ke
Ke=0.5 x m x v x v
Ke=0.5 x 5 x 6 x 6
Ke=90J
Kinetic energy of ship:
mass=m=120000kg
velocity=v=0.02m/s
Ke=0.5 x m x v x v
Ke=0.5 x 120000 x 0.02 x 0.02
Ke=24J
