Ask question

Ask question

All categories

2 years ago

13

A puck of mass 0.5100.510kg is attached to the end of a cord 0.827m long. The puck moves in a horizontal circle without friction

. If the cord can withstand a maximum tension of 126N, what is the highest frequency at which the puck can go around the circle without the cord breaking?

1 answer:

Mrac [35]2 years ago

7 0

Answer:2.74 Hz

Explanation:

Given

mass Puck $m=0.51 kg$

length of cord $L=0.827 m$

Maximum Tension in chord $T=126 N$

as the Puck is moving in a horizontal circle so maximum Tension in the string will be equal to centripetal force

$F_c=m\omega ^2L=T$

$126=0.51\times (\omega )^2\times 0.827$

$\omega =\sqrt{298.74}$

$\omega =17.28 rad/s$

$\omega =2\pi f$

$f=\frac{2\pi }{\omega }$

$f=2.74 Hz$

You might be interested in

The structural diversity of carbon-based molecules is determined by which properties?

Leokris [45]

Explanation:

The structural diversity of carbon-based molecules is determined by following properties:

1. the ability of those bonds to rotate freely,

2.the ability of carbon to form four covalent bonds,

3.the orientation of those bonds in the form of a tetrahedron.

5 0

2 years ago

In the two-slit experiment, monochromatic light of frequency 5.00 × 1014 Hz passes through a pair of slits separated by 2.20 × 1

asambeis [7]

Explanation:

It is given that,

Frequency of monochromatic light, $f=5\times 10^{14}\ Hz$

Separation between slits, $d=2.2\times 10^{-5}\ m$

(a) The condition for maxima is given by :

$d\ sin\theta=n\lambda$

For third maxima,

$\theta=sin^{-1}(\dfrac{n\lambda}{d})$

$\theta=sin^{-1}(\dfrac{n\lambda}{d})$

$\theta=sin^{-1}(\dfrac{nc}{fd})$

$\theta=sin^{-1}(\dfrac{3\times 3\times 10^8\ m/s}{5\times 10^{14}\ Hz\times 2.2\times 10^{-5}\ m})$

$\theta=4.69^{\circ}$

(b) For second dark fringe, n = 2

$d\ sin\theta=(n+1/2)\lambda$

$\theta=sin^{-1}(\dfrac{5\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{5c}{2df})$

$\theta=sin^{-1}(\dfrac{5\times 3\times 10^8}{2\times 2.2\times 10^{-5}\times 5\times 10^{14}})$

$\theta=3.90^{\circ}$

Hence, this is the required solution.

8 0

2 years ago

If a 5kg ball is rolling to the left and has a momentum of -25kg*m/s what is the velocity (not just speed) of the ball

Anna71 [15]

Answer:

The velocity of the ball is 5 m/s to the left.

Explanation:

-25kg*m/s divided by 5 kg gives

speed of -5 m/s

The velocity of the ball is 5 m/s to the left.

5 0

3 years ago

URGENT PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST !!!

Gnom [1K]

Answer: The first one

Explanation:

Because it’s the higher frequency

4 0

2 years ago

Read 2 more answers

How have we been able to construct detailed maps of surface features on venus?

frosja888 [35]

CORRECT ANSWER:

by using radar from spacecraft that were sent to orbit Venus

STEP-BY-STEP EXPLANATION:

A spacecraft is a device or mechanism designed to fly out into space. A type of automated satellite, spacecraft is used for a variety of purposes including communications, Earth observation, meteorology, navigation, space colonization, planetary exploration, and human and equipment transportation

4 0

2 years ago