how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch
1 answer:
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
Generally, the relationship between temperature, density and rate of vertical pressure is given as;
where;
- <em>ρ is density</em>
- <em>T is temperature</em>
- <em>dP is rate of change of vertical pressure</em>
Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
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Hello!
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.
Data:
Hooke represented mathematically his theory with the equation:
F = K * Δx
On what:
F (elastic force) = 2 N
K (elastic constant) = 4 N/cm
Δx (deformation or elongation of the elastic medium or distance from a spring) = ?
Solving:
simplify by 2
Answer:
B.) 1/2 cm
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I Hope this helps, greetings ... Dexteright02! =)
Answer:
a)
b)
c)
Explanation:
a) Immediately after the rod is released, <u>the rod is still horizontal but now subject to gravity.</u> Since one end of the rod is fixed, then the weight of the rod applies a torque. Then by Newton's Second Law, the acceleration can be found.
where I is the moment of inertia of the rod with respect to its fixed end, and α is the angular acceleration.
The net torque of the rod is
where r is the distance from center of the mass to the fixed end, so r = 0.4 m.
The weight of the rod is w = mg = 0.26 x 9.8 = 2.54 N.
So the net torque is τ = 1.01 Nm.
The moment of inertia of the rod is
So, the Newton's Second Law yields
<u>The relation between angular acceleration and linear acceleration is a = αr </u>
So, the linear acceleration of the rod is
b) Using the same relationship between angular acceleration and linear acceleration, the linear acceleration of the end of the rod can be found.
c) The conservation of energy can be used to find the velocity when the rod is vertical.
The linear velocity is v = ωr, so
v = 2.43 m/s.