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Hello!
Recall that the transformations form of a parabola is:
f(x) = ±a(b(x-h)) + k where:
a = vertical stretch/compression
b = horizontal stretch/compression
h = horizontal shift, x-coordinate of vertex
k = vertical shift, y-coordinate of vertex
In this instance, the parent function is f(x) = 3x^2. There is a vertical stretch of 3.
However, there is a point (7, -2) that needs to be included. Substitute these values into the transformation formula:
h = 7
k = -2
f(x) = 3(x - 7)² - 2 is the equation with (7, -2) as the vertex.
∠B = 77°, a = 7.42 and b = 12.61
Solution:
Given triangle ABC.
∠A = 35°, ∠C = 68°, c = 12
To find the measure of ∠B:
Sum of all the angles of the triangle = 180°
⇒ ∠A + ∠B + ∠C = 180°
⇒ 35° + ∠B + 68° = 180°
⇒ 103° + ∠B = 180°
⇒ ∠B = 180° – 103°
⇒ ∠B = 77°
To find the length of a and b:
The side opposite to angle A is a.
The side opposite to angle B is b.
Using law of sine,
Do cross multiplication, we get
Divide by 0.9271 on both sides, we get
⇒ a = 7.42
Again by law of sine,
Do cross multiplication, we get
Divide by 0.9271 on both sides, we get
⇒ b = 12.61
Hence ∠B = 77°, a = 7.42 and b = 12.61.