All categories

3 years ago

Help!! Will give brainliest

Mathematics

2 answers:

patriot [66]3 years ago

4 0

Answer:

Step-by-step explanation:

Arturiano [62]3 years ago

3 0

................................................................

You might be interested in

What is the value of 4 x minus 7 when x = 4?191623

katen-ka-za [31]

Solution:

Given:

$4x-7$

when x = 4,

$\begin{gathered} Substitute\text{ }x=4\text{ into }4x-7 \\ 4x-7=4(4)-7 \\ =16-7 \\ =9 \end{gathered}$

The answer is 9.

7 0

1 year ago

Solve 2x^2=11x+6 by factoring

Ede4ka [16]

Answer:

(x-6) (2x+1)

Step-by-step explanation:

1) move everything over to the left side, so subtract 11x and 6.

2x^2 -11x - 6 = 0

2)multiply 2(a term) with -6 (c term)

x^2 -11x -12

3) factor and find what multiples to -12 and adds up to -11. in this case its -12 and positive 1

(x-12) (x+1)

4) divide -12 and 1 by the original a term (2)

(x-6) (x+1/2)

5) move the denominator of 2 over to the x.

(x-6) (2x+1)

5 0

3 years ago

A quantitative observation? a. contains a number and a unit b. does not contain a number c. always makes a comparison

Naily [24]

Answer: A. contains a number and a unit

Step-by-step explanation:

Quantitative observations measure the quantity, or the amount, of a certain thing. Therefore they must always use a number value to measure the amounts, and a unit to signify what the amount is for.

3 0

1 year ago

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago

Just number 3 is fine please but if you could also 4

PIT_PIT [208]

Answer:

3. r = -8

4. x = -5

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define equation

2(-5r + 2) = 84

Step 2: Solve for r

Divide 2 on both sides: -5r + 2 = 42
Subtract 2 on both sides: -5r = 40
Divide -5 on both sides: r = -8

Step 3: Check

Plug in r into the original equation to verify it's a solution.

Substitute in r: 2(-5(-8) + 2) = 84
Multiply: 2(40 + 2) = 84
Add: 2(42) = 84
Multiply: 84 = 84

Here we see that 84 does indeed equal 84.

∴ r = -8 is a solution of the equation.

Step 4: Define equation

264 = -8(-8 + 5x)

Step 5: Solve for x

Divide both sides by -8: -33 = -8 + 5x
Add 8 to both sides: -25 = 5x
Divide 5 on both sides: -5 = x
Rewrite: x = -5

Step 6: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: 264 = -8(-8 + 5(-5))
Multiply: 264 = -8(-8 - 25)
Subtract: 264 = -8(-33)
Multiply: 264 = 264

Here we see that 264 does indeed equal 264.

∴ x = -5 is a solution of the equation.

8 0

2 years ago