All categories

3 years ago

Which types of dilation are the given scale factors?

Mathematics

2 answers:

Neporo4naja [7]3 years ago

7 0

Answer:

−4 is an expansion; 2.5 is an expansion; 2/3 is a contraction; and −3/4 is a contraction.

Step-by-step explanation:

In a dilation, a scale factor greater than 1 or less than -1 is an expansion. It will make the figure larger. This means that -4 is an expansion, since it is less than -1, and 2.5 is an expansion, since it is greater than 1.

A scale factor that is greater than -1 but less than 1 will be a contraction. It will make the figure smaller. This means that 2/3 is an expansion, since it is less than 1, and -3/4 is a contraction, since it is greater than -1.

VLD [36.1K]3 years ago

4 0

Expansion (-4) , Expasnsion ( 2.5 ) , Contraction ( 2/3) , and contraction ( -3/4)

You might be interested in

Use the side-splitter theorem to solve for x in the triangle below

hoa [83]

Answer:

Step-by-step explanation:

In this case the side-splitter theorem states that :

$\frac{x}{12} = \frac{6}{9} \\\\Then\\\\x = \frac{12*6}{9} = \frac{72}{9} =8$

8 0

4 years ago

Read 2 more answers

Need help with number 3a and 3b ?

kow [346]

Answer:

4 and 4.1

Step-by-step explanation:

because sqrrt17 is about 4.123 (memmorized) and it's rounded down to 4 and down to 4.1

8 0

3 years ago

A human hair was measured to have a diameter of 3.15 times 10 Superscript negative 3 inches. The width of a piece of paper was m

wolverine [178]

Answer:

43.21

Step-by-step explanation:

54 + 16

4 0

4 years ago

Need help with radical expression!!! It’s asking for a set of all x where the expression is defined in interval form!

gayaneshka [121]

Answer: (0, 25) ∪ (25, ∞)

Step-by-step explanation:

The expression is undefined when the denominator is equal to zero and when the radicand (expression inside the radical) is less than zero.

Let's deal with the denominator first by finding the x-values that would make the denominator equal to zero (these are the values that will NOT be included in the interval notation)

x - 5√x = 0

x = 5√x added 5√x to both sides

x² = 25x squared both sides

x² - 25x = 0 subtracted 25x from both sides

x(x - 25) = 0 factored the quadratic equation

x = 0 and x - 25 = 0 applied the Zero Product Property

x = 0 and x = 25 solved for x

So, x ≠ 0 and x ≠ 25

Next, let's deal with the radicand by setting the expressions inside the radicals to "greater than or equal to zero".

2√x and 5√x both have a radicand of x

x ≥ 0

Now, let's put it all together

x ≥ 0 and x ≠ 0 and x ≠ 25

so, x is between 0 and ∞ but not including 0 or 25.

Interval Notation: (0, 25) ∪ (25, ∞)

Reminder that interval notation uses a bracket [ ] when the value is included and a parenthesis ( ) when the value is not included. Infinity always uses a parenthesis since it is not an actual number.

6 0

3 years ago

In 1998 there were 1509 daily newspapers in the country. By 2003, there were only 1454 daily newspapers.

natta225 [31]

Answer:

The number of daily newspapers in 2000 is estimated in 1487

Step-by-step explanation:

Modeling Functions

Real-world situations are often modeled with mathematic functions. Functions allow making predictions and analysis to better understand and manage those situations

a. In our example, we know that in 1998 there were 1509 daily newspapers in the country. It gives us a starting point (0,1509), where the first coordinate is the years after 1998 and the second is the number of daily newspapers. The second point comes from the next data: by 2003 (5 years after 1998), there were 1454 daily newspapers. The new point is (5,1454).

b. Knowing the relationship between years after 1998 and the numbers of daily newspapers is linear, we can construct the function by using both points. The equation of a line, given the points (a,b) and (c,d) is

$\displaystyle y-b=\frac{d-b}{c-a}(x-a)$