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3 years ago

Someone help? I’m gonna fail pleaseeee. :(

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

8 0

Answer:

-8 < x, the answer is B

Step-by-step explanation:

Since its starting from -8 and your going to the greater side of the numberline teh variable will be greater than -8, whenever the circle is filled it just means greater than or equal to depending on which side its going. If its filled in, it means that its greater than or equal to or less than or equal to depending on which side its going towards.

Reminder:

<--------------- Negative side/Lower -----------------------> Positive side/Greater

Contact [7]3 years ago

8 0

Answer:

b is correct

Step-by-step explanation:

I just did it

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Evaluate square root of 24 - x when x = 6 . Write the answer in simplified radical form.?

timofeeve [1]

So, first we input 6
24 - 6 = 18
So we now need to find the square root of 18
If you're allowed to use a calculator, the square root is 4.242

But if you don't, let's get as close as we can:
√(9 * 2)
Because the square root of 9 is 3:
3 * √2

4 0

3 years ago

Help with 5b please . thank you.

Allushta [10]

Answer:

See explanation

Step-by-step explanation:

We are given f(x)=ln(1+x)-x+(1/2)x^2.

We are first ask to differentiate this.

We will need chain rule for first term and power rule for all three terms.

f'(x)=(1+x)'/(1+x)-(1)+(1/2)×2x

f'(x)=(0+1)/(1+x)-(1)+x

f'(x)=1/(1+x)-(1)+x

We are then ask to prove if x is positive then f is positive.

I'm thinking they want us to use the derivative part in our answer.

Let's look at the critical numbers.

f' is undefined at x=-1 and it also makes f undefined.

Let's see if we can find when expression is 0.

1/(1+x)-(1)+x=0

Find common denominator:

1/(1+x)-(1+x)/(1+x)+x(1+x)/(1+x)=0

(1-1-x+x+x^2)/(1+x)=0

A fraction can only be zero when it's numerator is.

Simplify numerator equal 0:

x^2=0

This happens at x=0.

This means the expression,f, is increasing or decreasing after x=0. Let's found out what's happening there. f'(1)=1/(1+1)-(1)+1=1/2 which means after x=0, f is increasing since f'>0 after x=0.

So we should see increasing values of f when we up the value for x after 0.

Plugging in 0 gives: f(0)=ln(1+0)-0+(1/2)0^2=0.

So any value f, after this x=0, should be higher than 0 since f(0)=0 and f' told us f in increasing after x equals 0.

8 0

2 years ago

How can i explain that i am useing multiplication to solve the proportion

kow [346]

In order for us to answer this question, more information is needed.

8 0

3 years ago

The graph of a line goes up and to the right when:

Afina-wow [57]

<h3><u>Answer:</u></h3>

Option: C is the correct answer.

c) the coefficient of x is positive

<h3><u>Step-by-step explanation:</u></h3>

We know that graph of a line goes up and to the right when the coefficient of x is positive.

Since we know that when a line goes up and to the right this means that the line is increasing and hence we will get a positive slope of the line and we know that the slope intercept of a line is given as:

$y=mx+c$