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3 years ago

Please I beg of y'all someone who is good with math- Please help-

Mathematics

1 answer:

BabaBlast [244]3 years ago

6 0

Answer:

1,Area = πr² Circumference = 2 πr So first we solve for r from area: 25 π = πr² 25 = r² r = 5 So we know that radius is 5 cm. Now substitute r to 5 in circumference formula: C = 2π(5) = 10π

2.126 cm2

3. Tank a

Step-by-step explanation:

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Draw a number line . Locate each integer on the number line.

kvv77 [185]

-5, -4, 0, 2, 3. From smallest to largest

7 0

3 years ago

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Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$

Therefore, we get

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98$

So, the sample standard deviation is 6.98.

3 0

3 years ago

How to find x using trigonometry

I am Lyosha [343]

Soh Cah Toa

Sine of the angle = opposite side over the hypotenuse

sin(42°) = 6.5/h
rearrange, solve for h
h = 6.5/sin(42°)
h = 9.7 cm

For the other triangle, the angle is unknown. I'd split it into two right triangles; down angle x since it is an isosceles it will be bisected into two equivalent triangles.

The hypotenuse we just found is now split in half. 9.7/2 = 4.9 base of the new smaller right triangle.

The new hypotenuse of the smaller triangle is 7.4 cm

Then you have..

sin(x/2) = 4.9/7.4
sin(x/2) = 0.67
use inverse sine function
arcSin(0.67) = x/2
41 = x/2
82° = x

There are many ways to solve this problem. This is just what I thought of first using trig.

3 0

3 years ago

Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −

larisa [96]

Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = $\frac{3}{2}$

d) zeros of the function are x = $\frac{-4}{3}$ and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

(x − 1) = 0 ..........(2)

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

x² = -1

x = √(-1) (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

x -4 = 0

x = 4

and,

for (x − 2)⁸ = 0

x - 2 = 0

x = 2

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

2x - 3 = 0

2x = 3

x = $\frac{3}{2}$

Thus,

zeros of the function are x = $\frac{3}{2}$

d) k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

(3x +4) = 0

3x = -4

x = $\frac{-4}{3}$

and,

for (x − 17)⁴ = 0

x - 17 = 0

x = 17

Thus,

zeros of the function are x = $\frac{-4}{3}$ and, x = 17

7 0

3 years ago

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p

zubka84 [21]

I think 80%

I also got stuck on it and searched it up I think its 80% but if I'm wrong I'm sorry

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