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pychu [463]
3 years ago
9

In the four-stroke internal combustion engine, fuel is ignited during the ~A. Compression B. Power C. Intake D.~ Exhaust stroke.

Physics
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

Explanation:

Compression

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Science Question please help
topjm [15]

Answer:

1.29 s

Explanation:

Given:

Δy = 1.40 m

v₀ = 0 m/s

a = 1.67 m/s²

Find: t

Δy = v₀ t + ½ at²

(1.40 m) = (0 m/s) t + ½ (1.67 m/s²) t²

t = 1.29 s

8 0
3 years ago
If an object falls and ends with a velocity of 58.8 m/s, how long was the<br><br> object falling?
tensa zangetsu [6.8K]

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m

The time to fall through the height is calculated as;

h =ut+  \frac{1}{2} gt^2\\\\h = 0 +  \frac{1}{2} gt^2\\\\h =  \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s

Therefore, the time taken for the object to fall is 6 s.

6 0
3 years ago
Find the minimum value of n in the Balmer series for which the predicted wavelength is in the ultraviolet region of the spectrum
d1i1m1o1n [39]

Answer:

 λ =365.4 nm

Explanation:

Boh's atomic model of the Hydrogen atom the energy of each level is

        Eₙ = - 13.606 / n²

where the synergy is in electonvotes and the value of E₀ = 13.606 eV is the energy of the base state of hydrogen.

An atomic transition occurs when an electron goes from an excited state and joins everything of lower energy.

                 ED = 13.606 (1 / n₀² - 1 /n_{f}^{2})

we are going to apply this relationship to answer slash.

 

At the beginning of the studies of atomic transitions, each group did not consider having a different name

name        Initial state

Lymman         1

Balmer           2

the final state is any other state sta the continuum that corresponds to n = inf

Let's look for the highest energy of the Balmer series

              ΔE = 13.606 (1/2² - 1 /∞)

              ΔE = 3.4015 eV

Let's use the Planck relation for the energy

                E = h f = h c /λ

                λ = h c / E

Let's reduce the energy to J

              E = 3.4015 eV (1.6 10⁻¹⁹ J / 1 eV) = 5.4424 10⁻¹⁹

            λ = 6.63 10⁻³⁴  3 10⁸ / 5.4424 10⁻¹⁹

            λ = 3.654 10⁻⁷ m

            λ = 3,654 10⁻⁷ m (10⁹ nm / 1m)

            λ =365.4 nm

this eta radiation in the ultraviolet range

5 0
3 years ago
Consider hitting a baseball with a bat. If we call the force on the bat against the ball the action force, identify the reaction
Nadya [2.5K]

Answer:

Explanation:

Action and reaction force are an integral part of third law of Newton . They are equal and opposite force - couple which act on two opposite objects. That is why they can not make a body in equilibrium.

In the given case, a bat is hit by a ball , at the point of contact , two equal and opposite forces emerge simultaneously , one acting on the ball and the other acting on the bat. As per the problem , force on the bat is called action . So the other force , that is force acting on the ball is called reaction force.

3 0
3 years ago
A 55.0-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300. What h
MariettaO [177]

Answer:

161.86 N

Explanation:

mass of box m= 55.0 kg

weight of the box, mg= 55×9.81

g here is acceleration due to gravity =9.81 m/sec^2

coefficient of friction between the box and the surface μ= 0.3

the friction force F_s= μmg= 0.3×55×9.81

=161.86 N

to move the ball horizontal force required is 161.86 N

8 0
3 years ago
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