Answer:
Minimum work = 5060 J
Explanation:
Given:
Mass of the bucket (m) = 20.0 kg
Initial speed of the bucket (u) = 0 m/s
Final speed of the bucket (v) = 4.0 m/s
Displacement of the bucket (h) = 25.0 m
Let 'W' be the work done by the worker in lifting the bucket.
So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.
Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

Therefore, the work done by the worker in lifting the bucket is given as:

Now, plug in the values given and solve for 'W'. This gives,

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.
The answer is 2.5 times heavier than on Earth !!
so the answer is C !!
Heat equation, Q = m.c.Δt
Here, c represents " the specific heat of the substance "
Hope this helps!
Answer:
600 and 1500 [ohm
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is the product of the current by the resistance, so we have:
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
<u>Therefore:</u>
R = V/I
R1 = 60/(40*10^-3) = 1500 [ohm]
R2 = 60/(100*10^-3) = 600 [ohm]
So the resistance should be among 600 and 1500 [ohm]
Answer:
yes
Explanation:
As the formula is α= ΔL/L*ΔT where alpha (α) is the sign of coefficient of linear expansion