Lamina and turbulent flow
Explanation:
mentioning about lamina and turbulent flow we could say that both form in different period of time
I think the situation is modeled by the scenario in the attached image. Some specific values seem to be missing (like the height of door
)...
The door forms a right triangles that satisfies

We also have

so if you happen to know the height of the door, you can solve for
and
.
is fixed, so

We can solve for the angular velocity
:

At the point when
and
ft/s, we get

Refer to the diagram shown below.
Given:
R = 6.37 x 10⁶ m, the radius of the earth
h = 3.58 x 10⁷ m, the height of the satellite above the earth's surface.
Therefore
R + h = 4.217 x 10⁷ m
In geosynchronous orbit, the period of rotation is 1 day.
Therefore the period is
T = (24 h)*(60 min/h)*(60 s/min) = 86400 s
The angular velocity is
ω = (2π rad)/(86400 s) = 7.2722 x 10⁻⁵ rad/s
Part (a)
The tangential speed is
v = (R+h)*ω
= (4.217 x 10⁷ m)*(7.2722 x 10⁻⁵ rad/s)
= 3066.7 m/s
= 3.067 km/s
Part (b)
The centripetal acceleration is
a = v²/(R+h)
= (3066.7 m/s)²/(4.217 x 10⁷ m)
= 0.223 m/s²
Answers:
(a) The speed is 3.067 km/s
(b) The acceleration is 0.223 m/s²
Answer:
The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".
Explanation:
Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.
Let's look at the speed of the car

We use movies and find lips

The moment is defined by

The moment change

Let's replace the speeds in this equation

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.
Answer:
the question this morning
Explanation:
90+70 look than