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2 years ago

6

Jared withdrew $5 from his savings account each month for 4 months. Write a multiplication expression for the total change in hi

s savings account balance. Then find the total change.

1 answer:

Ugo [173]2 years ago

3 0

5x4=the amount of change. His total change was $20

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Please help asap!!<br>Graph (x, y): x + 2y 6

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The answer is (, )=(6−2, )

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3 years ago

Simply 4 square root of 45

maksim [4K]

Answer : 12 square root 5

4 square root 45
4 square root 9 times square root 5
4 time 3 square root 5
12 square root 5

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3 years ago

The 200 students in a school band will attend and awards dinner. A random survey of 25 of these students was conducted to determ

vagabundo [1.1K]

C, there are 32 more students who want a beef meal than want a chicken meal.

200/25 = 8
12 x 8 = 96
8 x 8 = 64
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& 96 - 64 = 32

5 0

2 years ago

A bag contains five white balls and five black balls. Your goal is to draw two black balls.

umka21 [38]

Answer:

a.) the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b.) Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

Step-by-step explanation:

a) two balls are drawn at random .

total number of balls = 10

number of black balls = 5

number of white balls = 5.

the number of ways two balls can be drawn = $\binom{10}{2} = \frac{10!}{2! 8!} = \frac{10\times9}{2} = 45$

the number of ways two black balls can be drawn = $\binom{5}{2} = \frac{5!}{2! 3!} = \frac{5\times4}{2} = 10$

the probability that both the ball drawn are black = $\frac{10}{45} = \frac{2}{9}$

b) probability that First draw of two black balls = $\frac{2}{9}$

probability that first draw is of two white balls is and second draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9}$

Probability that first two draws are of white balls and the third draw is of

two black balls = $\frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}$

This is a geometric sequence and the final probability will be the sum of

all such probabilities, where we can take the the sequence to be an infinite series and the first term is $\frac{2}{9}$ and the common ratio is $\frac{2}{9}$ which is less than 1.

Sum of all the probabilities = $\frac{\frac{2}{9} }{1 - \frac{2}{9} } = \frac{\frac{2}{9} }{\frac{8}{9} } = \frac{2}{8} =\frac{1}{4} = 0.25$

3 0

3 years ago

Find the shaded sector and the length of the arc. Round to the nearest hundredth.

Dovator [93]

Answer:

Step-by-step explanation:

I'll show you how to do the first one; the other are exactly the same, so pay attention.

The formula for arc length is

$AL=\frac{\theta}{360}*2\pi r$ where θ is the central angle's measure. It just so happens that the measure of the central angle is the same as the measure of the arc it intercepts. Our arc shows a measure of 40°; this measure is NOT the same as the length. Measures are in degrees while length is in inches, or cm, or meters, etc. Going off that info, our central angle measures 40°. Filling in the formula and using 3.1415 for π:

$AL=\frac{40}{360}*2(3.1415)(3)$ . I'm going to reduce that fraction a bit (and I'll use the same reduction in the Area of a sector coming up next):

$AL=\frac{1}{9}*2(3.1415)(3)$ which makes

AL = 2.09 units. Now for Area of the Sector. The formula is almost identical, but instead uses the idea that the area of a circle is πr²:

$A_s=\frac{\theta}{360}*\pi r^2$ where θ is, again, the measure of the central angle (which is the same as the measure of the arc it intercepts). Filling in:

$A_s=\frac{1}{9}*(3.1415)(3)^2$ which simplifies a bit to

$A_s=\frac{1}{9}*(3.1415)(9)$ . As you can see, the 9's cancel each other out, leaving you with

$A_s=3.14$ units²

7 0

2 years ago

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