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RideAnS [48]
3 years ago
15

A sphere with a radius of 15 cm has the same volume as a cylinder with a radius of 5 cm. What is the height of the cylinder? A)

90 cm B) 120 cm C) 150 cm D) 180 cm
Mathematics
2 answers:
ahrayia [7]3 years ago
7 0

Answer: The answer is 180! I accidentally gave the guy on the bottom 1 star

kompoz [17]3 years ago
4 0
Vol of sphere = (4/3) pi r^3 and vol of cylinder = pi r^2 h

so

(4/3) pi 15^3 = pi (5)^2 h

(4/3) * 15^3 = 25h

h = [(4/3) * 15^3 ] / 25 = 180 cm
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Coefficient of b in expansion of (3+b)^4
Margarita [4]
Are you sure you want ONLY the coefficient of b?  If you expand this, you will have b in 3 of 4 terms.

According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:

                             1
                        1    2    1
                   1      3    3     1
              1       4     6     4     1

So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4

Here, you want (3 + b)^4.  Here's what that looks like:

3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]

Which coeff did you want?
4 0
3 years ago
Mrs. Lin had two dozen pencils. She gave them to four students and asked them to share equally among them. How many pencils shou
Mice21 [21]

Answer:

6 pencils each

Step-by-step explanation:

2 dozen = 24

24/4 = 6

3 0
3 years ago
Read 2 more answers
In the exercise, X is a binomial variable with n = 5 and p = 0.2. Compute the given probability. Check your answer using technol
Ronch [10]

Answer:

0.0512

Step-by-step explanation:

We are told in the question that X isa Binomial variable. Hence we solve this question, using the formula for Binomial probability.

The formula for Binomial Probability = P(x) = (n!/(n - x) x!) × p^x × q ^n - x

In the above question,

x = 3

n = 5

p = probability for success = 0.2

q = probability for failures = 1 - 0.2 = 0.8

P(x) = (n!/(n - x) x!) × p^x × q ^n - x

P(3) = (5!/(5 - 3) 3!) × 0.2^3 × 0.8^5-3

P(3) =( 5!/2! × 3!) × 0.2³ × 0.8²

P(3) = 10 × 0.008 × 0.64

P(3) = 0.0512

6 0
3 years ago
Suppose you can factor x^2 +bx +c as (x+p)(x+q) . If c<0, what could be the possible values of p and q?
Anna11 [10]
Ans: Option A

Explanation:
Let's solve it smartly!
Given expression: x^{2} + bx +c --- (A)
Factors: (x+p)(x+q)
Condition: c<0
Now let us expand (x+p)(x+q):
=> x^{2} + (p+q)x + pq  --- (B)

By comparing (B) with (A), we can say that:
pq = c --- (C)

Now, as the condition says, c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.

1) If p>0, q>0, it means c>0 since (+p)(+q) = (+c)(according to equation (C)). Condition is not met.
Hence, option B and D are wrong.

2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.

We are left with Option A:p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)).
Condition is MET!
Hence,
Ans: Option A: p= -3, q= 7
4 0
3 years ago
Read 2 more answers
What is the radius of a circle with a diameter of 36ft?
Anarel [89]

Answer:

18 ft

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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