Answer:
When a patient has a chipped tooth, it means that a small portion of their tooth is no longer there. Chipped teeth are one of the more common types of dental problems that general dentists deal with. However, chipped teeth do not grow back on any portion of a tooth and instead need to be repaired by a general dentist.
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Answer:
It's option d - Negative acceleration
Explanation:
- Let's start by demonstrate why <em>it's not option b - Speed : </em>Speed is a scalar quantity so it can not be represented by a vector
- Let's check that <em>the green vectors represent velocity</em> (velocity is a vector quantity, velocity is a direction aware, while speed is just a scalar)
- Now let's show that the circled vectors are acceleration vectors:
Mathematically position X , velocity V and acceleration A are:
and 
Where X, V, A are vectors and 
indicates the derivate a of a time is equal to b.
So, this show that acceleration is a rate respect of time of velocity ⇒ When acceleration is positive, velocity increments, when acceleration is negative, velocity decrements.
<em>The above explanation correspond to the motion map shown, getting demonstrated that the answer is D - Negative acceleration </em>
Answer:
The frequency of the simple harmonic motion of a 67.6 kg diver on the board = 2.48 Hz
Explanation:
The frequency in simple harmonic motion is related to spring constant and mass causing the motion through the relation
f = (1/2π) √(k/m)
When mass = 10 kg, f = 6.90 Hz,
6.9 = (1/2π) √(k/10)
(√(k/10) = 6.9×2π = 43.354
k/10 = 43.354² = 1879.57
K = 18795.7 N/m
When a diver of mass 67 kg climbs the diving board, the total mass on the diving board now becomes (10+67.6) = 77.6 kg
Spring constant of the diving board doesn't change,
So, the frequency is then given by
f = (1/2π) √(18795.7/77.6)
f = 2.48 Hz
A battery operated lamp because battery's don't use your own electricity. They come with electricity already.
Explanation:
Work done is given by the product of force and displacement.
Case 1,
1. A boy lifts a 2-newton box 0.8 meters.
W = 2 N × 0.8 m = 1.6 J
2. A boy lifts a 5-newton box 0.8 meters.
W = 5 N × 0.8 m = 4 J
3. A boy lifts a 8-newton box 0.2 meters.
W = 8 N × 0.2 m = 1.6 J
4. A boy lifts a 10-newton box 0.2 meters.
W = 10 N × 0.2 m = 2 J
Out of the four options, in option (2) ''A boy lifts a 5-newton box 0.8 meters'', the work done is 4 J. Hence, the greatest work done is 4 J.
