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NemiM [27]
3 years ago
9

At what angle should the axes of two polaroids be placed so as to reduce the intensity of the incident unpolarized light to 13.

Physics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

θ = 66.90°

Explanation:

we know that

I= \frac{I_0}{2}cos^2\theta

I= intensity of polarized light =1

I_o= intensity of unpolarized light = 13

putting vales we get

1= \frac{13}{2}cos^2\theta

⇒\theta=cos^{-1} \sqrt{\frac{1}{6.5} }

therefore θ = 66.90°

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Answer:

<em>Answer A. Fission, steam, turbine, electricity, cool water</em>

Explanation:

<u>Nuclear Energy Production </u>

Nuclear energy is produced by splitting uranium atoms in a process called fission. This generates heat and it's managed to produce steam, which later is used by a turbine generator to generate electricity. The heat must be taken out of the system, so a cooling process, usually involving water is the final step.

Because nuclear power plants don't burn fuel, they are known as clean energy sources.

Answer A. Fission, steam, turbine, electricity, cool water

6 0
3 years ago
Two microphones are connected to a
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Answer:

344.8 m/s

Explanation:

Looking for speed of sound  = meters / sec

       2 meters / .0058 seconds = 344.8 m/s

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2 years ago
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Reptile [31]

Answer:

There are two significant figures in 2.200 x 10^7

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3 years ago
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prohojiy [21]

Answer:

1. Test tube

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3.

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8 0
3 years ago
Birds resting on high-voltage power lines are a common sight. the copper wire on which a bird stands is 1.28 cm in diameter and
nekit [7.7K]

Answer:

8\cdot 10^{-4} V

Explanation:

First of all, let's find the cross-sectional area of the copper wire. The radius of the wire half the diameter:

r=\frac{d}{2}=\frac{1.28 cm}{2}=0.64 cm=6.4\cdot 10^{-3} m

So the area is

A=\pi r^2 = \pi (6.4\cdot 10^{-3} m)^2=1.29\cdot 10^{-4} m^2

Now we can calculate the resistance of the piece of copper wire between the bird's feet, with the formula:

R=\rho \frac{L}{A}

where

\rho=1.68\cdot 10^{-8} \Omega m is the resistivity of copper

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A=1.29\cdot 10^{-4} m^2 is the cross-sectional area

Substituting, we find

R=(1.68\cdot 10^{-8} m^2)\frac{4.12\cdot 10^{-2} m}{1.29\cdot 10^{-4} m^2}=5.4\cdot 10^{-6} \Omega

And since we know the current in the wire, I=149 A, we can now find the potential difference across the body of the bird, by using Ohm's law:

V=IR=(149 A)(5.4\cdot 10^{-6} \Omega)=8\cdot 10^{-4} V

4 0
3 years ago
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