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Dominik [7]
3 years ago
13

A campus bird spots a member of an opposing football team in an amusement park. The football player is on a ride where he goes a

round at angular velocity w at distance R from the center. The bird flies in a horizontal circle above him. Will a dropping the bird releases while flying directly above the person's head hit him? Ignore air resistance.
Physics
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

No..

Explanation:

As the bird releases the drop there is no internal force which will drive it into circular path but it will fall on tangent of the arc at the point of release because it has a tangential velocity same as bird. Path will be parabola in vertical plane.

As the person is on circular arc constantly moving it will never meet that drop.

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Phys-1A Horizontal Practice 2
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So basically you, then, finally, you
7 0
2 years ago
A 50 Ohm resistance causes a current of 5 milliamps to flow through a circuit connected to a battery. What is the power in the c
UkoKoshka [18]

Answer:0.00125 watts

Explanation:

resistance=50 ohms

Current=5 milliamps

Current=5/1000 milliamps

Current =0.005 amps

power=(current)^2 x (resistance)

Power=(0.005)^2 x 50

Power=0.005 x 0.005 x 50

Power=0.00125 watts

8 0
3 years ago
Read 2 more answers
If the current through a 20-ω resistor is 8.0 a , how much energy is dissipated by the resistor in 1.0 h ?
fiasKO [112]
1 hour = 3600 seconds.
Energy dissipated = I²Rt = 8²×20×3600 = 4608000 J
4 0
3 years ago
In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio
Keith_Richards [23]

Answer:

b. 0.25cm

Explanation:

You can solve this question by using the formula for the position of the fringes:

y=\frac{m\lambda D}{d}

m: order of the fringes

lambda: wavelength 500nm

D: distance to the screen 5 m

d: separation of the slits 1mm=1*10^{-3}m

With the formula you can calculate the separation of two adjacent slits:

\Delta y=\frac{(m+1)(\lambda D)}{d}-\frac{m\lambda D }{d}=\frac{\lambda D}{d}\\\\\Delta y=\frac{(500*10^{-9}nm)(5m)}{1*10^{-3}m}=2.5*10^{-3}m=0.25cm

hence, the aswer is 0.25cm

5 0
3 years ago
A woman on a bridge 95.6 m high sees a raft floating at a constant speed on the river below. She drops a stone from rest in an a
NARA [144]

Answer:

The speed of the raft is 1.05 m/s

Explanation:

The equation for the position of the stone is as follows:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the stone at time t

y0 = initial height

v0 = initial speed

t = time

g = acceleration due to gravity

The equation for the position of the raft is as follows:

x = x0 + v · t

Where:

x = position of the raft at time t

x0 = initial position

v = velocity

t = time

To find the speed of the raft, we have to know how much time the raft traveled until the stone reached the river. For that, we can calculate the time of free fall of the stone:

y = y0 + v0 · t + 1/2 · g · t²      (v0=0 because the stone is dropped from rest)

If we place the origin of the frame of reference at the river below the bridge:

0 m = 95.6 m - 9.8 m/s² · t²

-95.6 m / -9,8 m/s² = t²

t = 3.12 s

We know that the raft traveled (4.84 m - 1.56 m) 3.28 m in that time, then the velocity of the raft will be:

x/t = v

3.28 m / 3.12 s = v

v = 1.05 m/s

5 0
3 years ago
Read 2 more answers
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