Question

14. A unfair coin has the probability of heads

Answer 1

Answer :

the probability of tossing three heads in a row

$=\left( \frac{3}{8} \right)^{3} =\frac{27}{512} =0.052734375$

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the probability of tossing two heads followed by one tail

$=\left( \frac{3}{8} \right)^{2} \times \left( \frac{5}{8} \right) =\frac{45}{512}$

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the probability of two heads and one tail in any order

$=3\times \left( \frac{3}{8} \right)^{2} \times \left( \frac{5}{8} \right) =\frac{135}{512}$